Making an array of Objects and using overloaded [] in c++

Question

I created this class, say, Apple, and it has an overloaded operator [].
Then in another class, I made an array of apples, Apple stack[10].
Then when I was using stack[2] in an expression, instead of stack[2] being an object, the compiler is acting like it sees stack as stack[0], and then calling the operator [] and its parameter as 2.

Could you suggest a way I could calling stack[2] without being that way?

That seems weird; stack[2] should indeed give you the third Apple object. You should post your code - preferably, a simplified version that only includes the code that is necessary to demonstrate the problem. — Aasmund Eldhuset
– Aasmund Eldhuset, Commented Aug 11, 2012 at 18:49
oh, ok, that was another problem. The reason I did not post it is because it's a school assignment, and pretty big assignment basing on prevoius assignments we built upon. Thanks for the big offer for help :D — teamaster
– teamaster, Commented Aug 11, 2012 at 19:04

Nathan Andrew Mullenax · Accepted Answer · 2012-08-11 19:36:59Z

1

You could use a pointer to get array elements:

*(stack+2)[3]; // lookup element 2 and call its [] operator with 3

answered Aug 11, 2012 at 19:36

Nathan Andrew Mullenax

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Code-Apprentice · Accepted Answer · 2012-08-11 19:48:43Z

1

Based on the information given so far, stack[2] refers to an Apple object. You can also do stack[2][5] to call the overloaded operator[] in your Apple class.

answered Aug 11, 2012 at 19:48

Code-Apprentice

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akaHuman · Accepted Answer · 2012-08-11 20:33:53Z

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Providing the code would have been helpful.

However, suppose you have a variable x in the class Apple. You can access it using (stack+2)->x. This would work same as stack[2].x. And in case you want to use your overloaded operator, you may use it similarly. This wont confuse the compiler.

answered Aug 11, 2012 at 20:33

akaHuman

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