How to exit a loop on condition?

Question

$arr = array(1, 2, 3, 4);
foreach ($arr as $value) {
    $i=0;
    if($i==1||$i==2){continue;}
    echo $value;
    $i++;
}

I am a newbie of PHP, now i do a test, and i want to go out the loop not output 2 and 3, why the above code doesn't work?

You need to use break to get out, continue is to go to the next element in iteration. see php manual for more infos. — user180100
– user180100, Commented Aug 19, 2012 at 8:54

Madara's Ghost · Accepted Answer · 2012-08-19 09:07:28Z

7

That's because you set $i = 0; on each iteration (Hence your check for $i==1||$i==2 will never match). Variable initialization go outside the loop:

$arr = array(1, 2, 3, 4);
$i   = 0;
foreach ($arr as $value) {
    if ($i == 1 || $i == 2) {
        continue;
    }
    echo $value;
    $i++;
}

edited Aug 19, 2012 at 9:07

answered Aug 19, 2012 at 8:56

Madara's Ghost

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