Sending a parameter with space to another script in bash

Question

I need to send a variable to another script (BASH) and uset after in this first script. The code goes something like this:

read var
source myscipt.sh $var
echo $var

The problem is that if y put spaces when entering $var after sending it to myscript.sh I only have the first one.

NOTE: In myscript.sh I only use $1 does this have something to do with the problem?

Thanx!!!

Does myscipt.sh set var? When you source it, it runs in the same shell, and hence will modify the variables of the "parent" script. This is one of the reasons you should generally run scripts with ./myscript.sh rather than source — Gordon Davisson
– Gordon Davisson, Commented Sep 22, 2012 at 0:53

Stephane Rouberol · Accepted Answer · 2012-09-21 20:56:41Z

4

You need to use quotes. Thus var will be considered as only one parameter, even if it contains spaces.

source myscipt.sh "$var"

answered Sep 21, 2012 at 20:56

Stephane Rouberol

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4 Comments

But I dont really care how many parameters myscipt.sh recieves, I want to know why after that it only have one!

without seeing your script I only can guess that it manages $1 only (not $2, $3,...)

Stephane... yes indeed, in myscript.sh I only use $1 but does this affect my main script? I am not changing the variables...

please ask an other question and give code samples to show the difficulty you meet