Setting default JRE version via batch file

Question

I have JRE 6 and JRE 7 both installed on my Windows 7 workstation. I want to set the default Java to JRE 6.

I've tried setting the JAVA_HOME variable to C:\Program Files (x86)\Java\JRE6\bin and I've also tried messing with the registry.... none of these are working for me

I don't want to uninstall and i don't want to use the GUI control panal Java Console to disable JRE 7.

I need to automate a way to set JRE 1.6 as the default java?

As the jre is used mainly by the browsers and they search the current version in registry I think you should see what was a a problem with editing registry values.The version (if the machine is 64 bit) is written n \HKLM\SOFTWARE\Wow6432\JavaSoft\Java Runtime Environment\CurrentVersion and you just need to set the version ot 1.7 — npocmaka
– npocmaka, Commented Oct 22, 2012 at 13:25

PbxMan · Accepted Answer · 2012-10-22 13:21:27Z

1

You should set the /bin/java (java.exe in MSWindows) in your path and put in in the first place.Steps 16, 17, and 18

answered Oct 22, 2012 at 13:21

PbxMan

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Yogendra Singh · Accepted Answer · 2012-10-22 13:22:10Z

0

JAVA_HOME should point root folder of java e.g. C:\Program Files (x86)\Java\JRE6. Please try.

answered Oct 22, 2012 at 13:22

Yogendra Singh

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