In JavaScript/jQuery, how to retrieve the url of an ajax call after the call is done? [duplicate]

Question

I'm trying to write a web program in JavaScript where I have to make multiple ajax calls, and I need to figure out how to get the url after making an ajax call to the url. The ajax calls are made in a for loop that loops through an array of urls. So the code for the ajax request and the function that processes the return of the request look something like this:

requester = function(url){
    $.ajax({
        url : "http://url of my proxy?url=" + escape(url),
        type : "GET",
        data-type : "xml"
    }).done(dataProcessor);
};

dataProcessor = function(data){
    //a bunch of code, including things where I must have the url for the ajax request
};

So, how can I get that url?

Why not function requester(url) { ... }?

Matt Ball
– Matt Ball

2012-11-14 04:10:49 +00:00
Commented Nov 14, 2012 at 4:10 — Matt Ball
– Matt Ball, Commented Nov 14, 2012 at 4:10

jfriend00 · Accepted Answer · 2012-11-14 04:10:12Z

0

You can simply save it and pass it to your function:

requester = function(url){
    var fullURL = "http://url of my proxy?url=" + escape(url)
    $.ajax({
        url : fullURL,
        type : "GET",
        data-type : "xml"
    }).done(function(data) {dataProcessor(data, fullURL)});
};

dataProcessor = function(data, url){
    //a bunch of code, including things where I must have the url for the ajax request
};

answered Nov 14, 2012 at 4:10

jfriend00

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1 Comment

orangekitty215 Over a year ago

Ah, thank you!! I wasn't sure how to pass a parameter when a function is called this way because I'm new to web programming, but this makes perfect sense now, and it works! :)

NoPyGod · Accepted Answer · 2012-11-14 04:08:59Z

0

Take advantage of closures

requester = function(url){
    $.ajax({
        url : "http://url of my proxy?url=" + escape(url),
        type : "GET",
        data-type : "xml"
    }).done(function(data) {

         alert(url);

    });
};

answered Nov 14, 2012 at 4:08

NoPyGod

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Comments

I Hate Lazy · Accepted Answer · 2012-11-14 04:10:27Z

-1

It's available from the this value, which is the jqXHR object.

dataProcessor = function(data){
    console.log(this.url);
};

answered Nov 14, 2012 at 4:10

I Hate Lazy

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1 Comment

I Hate Lazy Over a year ago

Down-vote on a correct and fast solution?

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