Check if ALL elements in 2D-Array have same value

Question

if we have a 1D array, we could use the following to see if all elements are equal to 3:

int[] t = Enumerable.Repeat(3, 10).ToArray();

if (t.All(item => item.Equals(3))) MessageBox.Show("all elements equals to 3");

but if I have a 2D-array, how could I check if all elements are equal to 3 ( without any for-Loops ):

    int[,] t2D= new int[,] { { 3, 3 }, { 3, 3 }, { 3, 3 }, { 3, 3 } };

    if( CHECK IF ALL ELEMENTS IN **t2D** are equal to 3) 

               {
                MessageBox.Show("all elements equals to 3");
               }

What should I put in If-statement?

Without any for loops? ok... Considered that All() is using for loops? No need to be ashamed of for() or foreach() — lboshuizen
– lboshuizen, Commented Nov 15, 2012 at 1:09
@lboshuizen: If you define a 2D array: int[,] tt = new int[3, 4]; .All() is not part of the methods that you could use. Try tt.All => no method has been defined for 2D array case — farzin parsa
– farzin parsa, Commented Nov 15, 2012 at 3:08

Sergey Berezovskiy · Accepted Answer · 2012-11-15 01:31:07Z

3

2D-array is an enumerable type (but it implements non-generic IEnumerable). And it's enumerator enumerates over all items in 2D-array. So, only thing you need to do - cast its items to int (thus retrieving IEnumerable<int>) and apply All

t2D.Cast<int>().All(x => x == 3)

edited Nov 15, 2012 at 1:31

answered Nov 15, 2012 at 1:12

Sergey Berezovskiy

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2 Comments

farzin parsa Over a year ago

@ lazyberezovsky: aw,thanks. just for the purpose of learning, how could I differentiate between non-generic Inumerable and generic Inumerables? or lets rephrase it: why generic types support .All() method or non-generic not?

Sergey Berezovskiy Over a year ago

@farzinparsa All() is an extension method on type IEnumerable<T> (defined in Enumerable class)or IQueryable<T>. Thats why only generic sequences support Linq methods.

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