How to call a prototype function inside another prototype function without losing context

Question

I have this CODE:

var MyObj = (function() {
    //Constructor
    var MyObj= function(){
        this.myArray = [1,2,3];
    }

    MyObj.prototype = {
        myFunc: function(){
            alert(this.myArray.toString());                
        },
        myFuncCaller: function(){            
            MyObj.prototype.myFunc();                
        }
    };
    return MyObj;      
})();

var myObj = new MyObj();
myObj.myFunc();

//This line will throw an exception because this.myArray is undefined
myObj.myFuncCaller();

Why is this.myArray undefined? I know I'm doing something wrong, how would be the correct way to do it?

SLaks · Accepted Answer · 2012-11-28 17:39:49Z

4

Just use this:

this.myFunc();

When you call a function in Javascript, this is set to the expression you called it on.
In your code, for example, this in myFunc() is MyObj.prototype.

answered Nov 28, 2012 at 17:39

SLaks

891k182 gold badges1.9k silver badges2k bronze badges

Sign up to request clarification or add additional context in comments.

Collectives™ on Stack Overflow

How to call a prototype function inside another prototype function without losing context

1 Answer 1

Comments

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

1 Answer 1

Comments

Your Answer

Sign up or log in

Post as a guest

Related