15

I want to remove any numbers from the end of a string, for example:

"TestUser12324" -> "TestUser"
"User2Allow555" -> "User2Allow"
"AnotherUser" -> "AnotherUser"
"Test123" -> "Test"

etc.

Anyone know how to do this with a regular expression in Java?

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3 Answers 3

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38

This should work for the Java String class, where myString contains the username:

myString = myString.replaceAll("\\d*$", "");

This should match any number of trailing digit characters (0-9) that come at the end of the string and replace them with an empty string.

.

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6

Assuming the value is in a string, s:

    s = s.replaceAll("[0-9]*$", "");
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0

This should be the correct expression:

(.+[^0-9])\d*$
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1 Comment

If the string is "Another1Userwee a8 8 8" , then what's the regex to remove all the trailing numbers so that output would come as "Another1Userwee a"

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