Accessing PHP valiables fields names without using intermediate variables [duplicate]

Question

Possible Duplicate:
Get PHP class property by string

Is there a cleaner way to do this? it does not compile

$object1->name = 'my_name';
$object1->address = 'address';
$object2->somefield->($object1->name) = $object1;

it works only if i assign to another variable $object1->name

$object1->name = 'my_name';
$object1->address = 'address';
$temp = $object1->name;
$object2->somefield->$temp = $object1;

aykut · Accepted Answer · 2012-12-11 15:41:39Z

9

Try this:

$object2->somefield->{$object1->name} = $object1;

answered Dec 11, 2012 at 15:41

aykut

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3 Comments

+1, even this answer got too much up-votes :P

Good! Thank you!! It there some documentation to this somewhere? :)