preg_replace with pattern and subject array returning empty array

Question

I want a simple way to delete elements of $badwords from $keywords.

What I have (as an example)

$keywords = array('sebastian','nous','helene','lol'); //it could be anything in fact
$badwords = array('nous', 'lol', 'ene', 'seba'); //array full of stop words that I won't write here
$filtered_keywords = array_filter(preg_replace($badwords,'',$keywords), 'strlen');
print_r($filtered_keywords);

What I expected

Array ( [0] => samaha [1] => helene )

What I got

 Sweet nothing :)

I tried to use str_ireplace but it went bad because it was replacing within the strings in my array.

What is in $excluded_words?

Sverri M. Olsen
– Sverri M. Olsen

2012-12-26 07:35:46 +00:00
Commented Dec 26, 2012 at 7:35 — Sverri M. Olsen
– Sverri M. Olsen, Commented Dec 26, 2012 at 7:35
$excluded_words should be $badwords? or i dint get it?

Mithun Satheesh
– Mithun Satheesh

2012-12-26 07:36:20 +00:00
Commented Dec 26, 2012 at 7:36 — Mithun Satheesh
– Mithun Satheesh, Commented Dec 26, 2012 at 7:36
Corrected my example but code was ok. Sorry for that.

Wistar
– Wistar

2012-12-26 07:38:55 +00:00
Commented Dec 26, 2012 at 7:38 — Wistar
– Wistar, Commented Dec 26, 2012 at 7:38

Sivagopal Manpragada · Accepted Answer · 2012-12-26 07:39:25Z

3

$keywords = array('sebastian','nous','helene','lol');

$badwords = array('nous', 'lol', 'ene', 'seba'); 

$filtered_keywords=array_diff($keywords,$badwords);

answered Dec 26, 2012 at 7:39

Sivagopal Manpragada

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Comments

Artem L · Accepted Answer · 2012-12-26 07:39:02Z

2

use array_diff

var_dump(array_diff($keywords, $badwords));
array(2) {
  [0]=>
  string(9) "sebastian"
  [2]=>
  string(6) "helene"
}

answered Dec 26, 2012 at 7:39

Artem L

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Comments

Hanky Panky · Accepted Answer · 2012-12-26 07:36:52Z

1

Incorrect Array name most probably

$filtered_keywords = array_filter(preg_replace($excluded_words,'',$keywords), 'strlen');

it isnt $excluded_words, it is $badwords

answered Dec 26, 2012 at 7:36

Hanky Panky

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Comments

irrelephant · Accepted Answer · 2012-12-26 07:38:52Z

1

You're missing a semicolon after

$keywords = array('sebastian','nous','helene','lol')

And you can use array_diff:

$filtered_keywords = array_diff($keywords, $badwords);

answered Dec 26, 2012 at 7:38

irrelephant

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Comments

Ramesh Moorthy · Accepted Answer · 2012-12-26 07:41:30Z

0

You missed the slashes / in the $badwords. and you missed the semicolon ; at the end of the fist line. Try this code:

<?php

$keywords = array('sebastian','nous','helene','lol'); //it could be anything in fact
$badwords = array('/nous/', '/lol/', '/ene/', '/seba/'); //array full of stop words that I won't write here

$filtered_keywords = array_filter(preg_replace($badwords,'',$keywords), 'strlen');

echo print_r($filtered_keywords);

?>

answered Dec 26, 2012 at 7:41

Ramesh Moorthy

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