http://docs.python.org/2/library/datetime.html
I use the today function to get current date, how to perform simple arithmetic on this object so that I can reduce or increase the current date by 1 or 2 (i.e. yesterday or day-before yesterday)
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You may be interested by the dateutil python libraryluc– luc2013-01-15 10:03:56 +00:00Commented Jan 15, 2013 at 10:03
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datetime has timedelta module. You can use it.pranshus– pranshus2013-01-15 10:32:46 +00:00Commented Jan 15, 2013 at 10:32
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1 Answer
you can do the following
In [6]: import datetime
# Today
In [7]: datetime.datetime.now()
Out[7]: datetime.datetime(2013, 1, 15, 15, 31, 10, 760000)
# Tomorrow's date
In [8]: print datetime.datetime.now() + datetime.timedelta(days=1)
2013-01-16 15:31:15.336000
# Day after tomorrow's day
In [9]: print datetime.datetime.now() + datetime.timedelta(days=2)
2013-01-17 15:31:52.601000
# Yesterday's date
In [10]: print datetime.datetime.now() - datetime.timedelta(days=1)
2013-01-14 15:32:00.081000
also works with datetime.datetime.today()
In [15]: datetime.datetime.today()
Out[15]: datetime.datetime(2013, 1, 15, 15, 34, 37, 55000)
In [16]: datetime.datetime.today() + datetime.timedelta(days=1)
Out[16]: datetime.datetime(2013, 1, 16, 15, 34, 47, 560000)