Why is setting my widget option evaluating to an object instead of being passed as a key and value?

Question

I've created (or am trying to create) a jQuery UI widget using the widget factory and have set up my _setOptions method this way as found here: http://wiki.jqueryui.com/w/page/12137708/How%20to%20use%20jQuery%20UI%

_setOptions: function (key, value) {
    if (this.options[key] !== value) {
        this.options[key] = value;
        this._update();
    }
},

This is my options object:

 options: {
            title: 'Legend',
            colors: ['#0000CC', '#6600CC', '#009900', '#990000', '#6600FF', '#CCFF00', '#FF9900', '#000000', '#FFFFFF', '#00FF00'],
            items: undefined
        }

However, when I pass in a new title value for my legend widget, I am getting an object for key instead of a key and value in _setOptions. value comes in undefined, for the record.

$('#myLegend').legend('option', 'title', 'New Title');

The key object

My expectations were this:

key==='title'
value==='New Title'

If there some common misconception I'm missing or can anyone think of why this would be happening?

user400654 · Accepted Answer · 2013-01-28 19:43:17Z

1

The _setOptions method does get called with an object for the first argument, it contains key/value pairs of all the options changed.

http://api.jqueryui.com/jQuery.widget/#method-_setOptions

what you probably meant to use was _setOption rather than _setOptions

answered Jan 28, 2013 at 19:43

user400654

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1 Comment

Yatrix Over a year ago

Dammit. Instead of accepting blame, I will place blame on the fact today is Monday. Thanks, Kevin.

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