Simple regex in python to filter out one word

Question

I have the output as

app_39    281   33    94332  21228 ffffffff afd0c51c S abc
app_39    292   33    103864 30060 ffffffff afd0c51c S cvc.notes
app_39    303   33    94332  21344 ffffffff afd0c51c S cocccs:syncHandler
app_39    312   33    94332  21404 ffffffff afd0c51c S cccs:cacheHandler
app_39    321   33    94332  21344 ffffffff afd0c51c S cocccs:dailyReceiver

This whole output is stored in a variabble called outresult

How can I use python to extract the 2nd word of the second line? that is 292 and store it in a variable?

Do you have this output as a list? As a multiline string? As a file or a stream like stdin? — Tim Pietzcker
– Tim Pietzcker, Commented Mar 1, 2013 at 6:53
No, it is not STO-RED IN A VA-RIA-B-LE gna gna gna. There are no variables get out of it by Python. There are only identifiers and objects. — eyquem
– eyquem, Commented Mar 1, 2013 at 7:25

Explosion Pills · Accepted Answer · 2013-03-01 06:54:09Z

8

output.split('\n')[1].split()[1]

No regex needed.

answered Mar 1, 2013 at 6:54

Explosion Pills

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2 Comments

daramarak Over a year ago

No regex needed, and now you got 0 problems +1.

Jon Clements Over a year ago

.split(None, 2)[1] may be slightly more efficient as you only actually require 2 splits to get what you want.

eyquem · Accepted Answer · 2013-03-01 07:32:17Z

0

ss = '''app_39    281   33    94332  21228 ffffffff afd0c51c S abc
app_39    292   33    103864 30060 ffffffff afd0c51c S cvc.notes
app_39    303   33    94332  21344 ffffffff afd0c51c S cocccs:syncHandler
app_39    312   33    94332  21404 ffffffff afd0c51c S cccs:cacheHandler
app_39    321   33    94332  21344 ffffffff afd0c51c S cocccs:dailyReceiver'''

def lect(inp,nline,nw):
    gen = (xli.split() for i,xli in enumerate(inp.splitlines()) if i==nline-1)
    return gen.next()[nw-1]


print lect(ss,2,2)

answered Mar 1, 2013 at 7:32

eyquem

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