Pointer in Vector

Question

std::vector<int*> * vec=new std::vector<int*>();
int* p=new int();
int* q=new int();
vec.push_back(p);
vec.push_back(q);
.
.
.
vec.clear();

My Question is will the memory is deallocated ???

Correct me if I'm wrong, but vector::push_back takes an argument of type T and not void? — user529758
– user529758, Commented Mar 5, 2013 at 6:27
@H2CO3 Yes that is correct, but it is not particularly relevant to the question. — ApproachingDarknessFish
– ApproachingDarknessFish, Commented Mar 5, 2013 at 6:29

Spook · Accepted Answer · 2013-03-05 06:27:33Z

3

The memory holding the pointers, yes. The memory holding pointer's contents, no. Also, you should free the vector itself by writing delete vec; at the end of the program, but I guess, that it's not what you are asking for.

answered Mar 5, 2013 at 6:27

Spook

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ForEveR · Accepted Answer · 2013-03-05 06:33:38Z

2

No. You should use delete, when you use new (and not use smart-pointers). And for elements of vector - no, the memory will not be deallocated, you should use delete on each element in vector. Something like

std::for_each(vec.begin(), vec.end(), [](const int* p) { delete p; });

edited Mar 5, 2013 at 6:33

answered Mar 5, 2013 at 6:27

ForEveR

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