Sort multiple values in arrays

Question

I have an array with multiple locations for different states.

{"location":"Lekki Phase 1","state":"abc","country":"Nigeria"},
{"location":"Lekki Phase 2","state":"xyz","country":"Nigeria"},
{"location":"Osapa London1","state":"def","country":"Nigeria"},
{"location":"Lekki Phase 2","state":"abc","country":"Nigeria"},
{"location":"Lekki Phase 3","state":"xyz","country":"Nigeria"},
{"location":"Osapa London 2","state":"def","country":"Nigeria"},..........

Now i can make an array for different states with no duplicate state , like

 {"abc","xyz","def"}

But what i want is to display all locations state wise in a table.

How can i do this??

this might helps you :) stackoverflow.com/questions/2766994/… Must — mustafa96m
– mustafa96m, Commented Mar 15, 2013 at 6:03

βhargavḯ · Accepted Answer · 2013-03-15 06:59:19Z

1

Using NSPredicate we can efficiently filter this . I have tried and tested working for me.

Here 'allDataArray' is array with dictionaries, You can replace your array here (the first one in your post)

    NSMutableArray *allDataArray = [[NSMutableArray alloc] init];
    NSMutableDictionary *dict1 = [[NSMutableDictionary alloc] init];
    [dict1 setObject:@"Lekki Phase 1" forKey:@"location"];
    [dict1 setObject:@"abc" forKey:@"state"];
    [dict1 setObject:@"Nigeria" forKey:@"country"];
    [allDataArray addObject:dict1];

    dict1 = [[NSMutableDictionary alloc] init];
    [dict1 setObject:@"Lekki Phase 2" forKey:@"location"];
    [dict1 setObject:@"xyz" forKey:@"state"];
    [dict1 setObject:@"Nigeria" forKey:@"country"];
    [allDataArray addObject:dict1];

    dict1 = [[NSMutableDictionary alloc] init];
    [dict1 setObject:@"Lekki Phase 2" forKey:@"location"];
    [dict1 setObject:@"abc" forKey:@"state"];
    [dict1 setObject:@"Nigeria" forKey:@"country"];
    [allDataArray addObject:dict1];

    dict1 = [[NSMutableDictionary alloc] init];
    [dict1 setObject:@"Lekki Phase 3" forKey:@"location"];
    [dict1 setObject:@"xyz" forKey:@"state"];
    [dict1 setObject:@"Nigeria" forKey:@"country"];
    [allDataArray addObject:dict1];
    //NSLog(@"%@",allDataArray);

    NSArray *state = [NSArray arrayWithObjects:@"abc",@"xyz", nil];

    NSMutableArray *locationInState = [[NSMutableArray alloc] initWithCapacity:[state count]];
    for(int i=0; i< [state count]; i++)
    {
        NSMutableArray *filteredarray = [[allDataArray filteredArrayUsingPredicate:[NSPredicate predicateWithFormat:@"(state == %@)", [state objectAtIndex:i]]] mutableCopy];
        for(int j=0; j<[filteredarray count];j++)
        {
            NSDictionary *dict = [filteredarray objectAtIndex:j];
            [filteredarray replaceObjectAtIndex:j withObject:[dict valueForKey:@"location"]];
        }
        [locationInState addObject:filteredarray];
    }
    NSLog(@"%@",locationInState);

Here locationInState array contains all location for filetred state. You can map them easily by index.

Result is

(
    (
        "Lekki Phase 1",
        "Lekki Phase 2"
    ),
        (
        "Lekki Phase 2",
        "Lekki Phase 3"
    )
)

edited Mar 15, 2013 at 6:59

answered Mar 15, 2013 at 6:31

βhargavḯ

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3 Comments

Purva Over a year ago

Thanks for reply. What does "all" refers to here??

βhargavḯ Over a year ago

allDataArray is array with dictionary the first one you have. just try and let me know if works for you.

Purva Over a year ago

I have tried your code but it crashed with error 'NSUnknownKeyException', reason: '[<__NSCFString 0x9ee8e50> valueForUndefinedKey:]: this class is not key value coding-compliant for the key state.

Community · Accepted Answer · 2017-05-23 12:04:54Z

1

First It not array but it is Dictionary.

NSMutableDictionary * newDict = [NSMutableDictionary dictionaryWithCapacity:[OLdDict count]];
for(id item in [OLdDict allValues]){
    NSArray * keys = [OLdDict allKeysForObject:item];
    [newDict setObject:item forKey:[[OLdDict allKeysForObject:item] objectAtIndex:0]];
}

edited May 23, 2017 at 12:04

CommunityBot

11 silver badge

answered Mar 15, 2013 at 6:11

user2289379

Comments

CodaFi · Accepted Answer · 2013-03-15 06:18:28Z

NSMutableDictionaries can act as uniquing collections (because they replace objects for keys if the same key is used twice). We can also take advantage of the fact that NSString is generally a constant address location, and funnel each one of those dictionaries into an array. To unique out each array of dictionaries, it would be far easier to wrap them in an object, but here goes:

-(void)uniquingSort {
    //Setup collections for the uniquing process
    NSMutableArray *datasource = //...
    NSMutableIndexSet *hits = [NSMutableIndexSet indexSet];
    NSMutableDictionary *uniquingDict = @{}.mutableCopy;

    //Setup an index for the indexed set
    int idx = 0;

    //iterate through the array of dictionaries
    for (NSArray *arrOfDicts in datasource) {
        //get the dictionary we want to unique against
        NSDictionary *innerDict = arrayOfDicts[1];
        //do we have a dupe?  If so, add its index to the index set
        if (uniquingDict[innerDict[@"state"]] != nil)
            [hits addIndex:idx];
        uniquingDict[innerDict[@"state"]] = innerDict[@"state"];
        idx++;
    }
    //cut out all the hits till we are only uniqued for the "state" key
    [datasource removeObjectsAtIndexes:hits];
}

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