JQuery If Statement Returns same number regardless of the input

Question

I have a really easy HTML form and some JQuery to calculate a figure.

The issue I have is that the if statement returns the same number irrelevant of the input:

    $(document).ready(function()
    {
        $('input').change(function()
        {
            var behind = escape($('#behind').val());
            var speed = parseInt($('#speed').val());
            var diff;

if (behind = "nse") { diff = '0.83'; }
if (behind = "0.5") { diff = '1.66'; }
if (behind = "0.75") { diff = '2.49'; }

var hsr = speed-diff;
$('#hsr').html(hsr);

        });
    });

If I input nse into the box the calculation uses diff = '2.49' instead of diff = '0.83' as I've programmed.

The jsFiddle page with the full code is at http://jsfiddle.net/Jucna/1/

Please could someone explain what is wrong with the code?

Thanks in advance.

Adil · Accepted Answer · 2013-03-21 11:11:36Z

3

Use comparison operator == instead of assignment operator = in if statement.

Live Demo

if (behind == "nse") { diff = '0.83'; }
if (behind == "0.5") { diff = '1.66'; }
if (behind == "0.75") { diff = '2.49'; }

answered Mar 21, 2013 at 11:11

Adil

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Comments

sasi · Accepted Answer · 2013-03-21 11:12:10Z

1

== compare

= assign

if (behind == "nse")

answered Mar 21, 2013 at 11:12

sasi

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Comments

Mark Walters · Accepted Answer · 2013-03-21 11:13:27Z

1

Missing a = in your if statements

if (behind == "nse") { diff = '0.83'; }
if (behind == "0.5") { diff = '1.66'; }
if (behind == "0.75") { diff = '2.49'; }

Using one = assigns a value rather than comparing it.

answered Mar 21, 2013 at 11:13

Mark Walters

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