I would like to search in an Array if there is a key that has a stringlength of exactly 5 characters and further on it must be of type integer.
I tried:
$key = array_search( strlen( is_int($array)=== true) === 5 , $array);
but this does not work. So I would like to know if it exists and which key it is.
Thanks alot.
How about:
$filtered = array_filter($array, function($v){
return !!(is_int($v)&&strlen($v)==5);
});
Essentially array_filter iterates over each element of the array passing each value $v to a callable function. Depending on your desired conditions it returns a boolean (true or false) as to whether it is kept in the resultant $filtered array.
the !! is not strictly necessary as (...) will ensure boolean is cast correctly but the exclamation marks are just syntactic sugar - personal preference for readability.
That's not how array_search() works. It searches the value for a matching string, and returns a key. If you want to search a key, your best bet is to simply iterate over it.
foreach ($array as $key => $value) {
if (strlen($key) === 5) {
echo $key . ": " . $value;
break; //Finish the loop once a match is found
}
}
here is sample example to compare value with integer and exact 5 character
$array = array(12345,'asatae');
$key_val = array();
foreach($array as $each_val){
if(is_int($each_val) && strlen($each_val) == 5){
$key_val[] = $each_val;
}
}
echo "<pre>";
print_r($key_val);
you output will be like
Array
(
[0] => 12345
)
Notice : in array must be integer value not quotes
like array(23, "23", 23.5, "23.5")
23 is integer with first key..
array_search will not work like this try
foreach ($array as $key => $value) {
if ((strlen($value) == 5) && is_int($value))
{
echo $key . ": " . $value;
}
}
You can use array_walk
array_walk($array, function(&$value, $index){
if (strlen($value) == 5 && (is_int($index))) echo "$index:$value";
});
array walk iterates through each element and applies the user defined function
