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html form

<html><body>
<form action="process.php" method="post">
Headline:<input type="text" name="head"><br>
Content:<Textarea rows="4" cols="50" name="cont"></textarea>
</form>
</html>

my table structure two fields are headline,content.

Filling the form: Headline- "this is crazy" Content- "here i want to put image like this.. <img src="$image" /> "

Process.php

in this i get Headline and content from form in two php variable $headline=$_POST['head']; $content=$_POST['cont'];

here i have one variable $image which contains address of image like: $image contains "img\thumb\2.jpg"

i've to insert $headline and $content into table.

problem whenever i insert headline and content into table... headline goes fine into table..but in content it shows: "here i want to put image like this.. &lt;img src=&quot;$image&quot; /&gt; "

why $image actual value is not getting parsed? any solution?

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3
  • Can you show the full code of the page, or at least the section, that has the content and <img /> tag? The HTML form you have doesn't have the image tag in it and your sample output doesn't help much either. Commented Apr 26, 2013 at 5:12
  • ok let me explain.... firstly i upload image thru different php script, and store its address in "$image". now say $image look like "$image=img\thumb\2.jpg".Thru my html form im uploading "headline"and "content" in database using INSERT. I want to use $image variable in "content"field of html form. but it takes "content" containg $image variable as string. when i open table to see content it contains "$image" instead of "img\thumb\2.jpg" . Commented Apr 26, 2013 at 7:00
  • @newfurniturey: i will upload code soon.. Commented Apr 26, 2013 at 7:02

4 Answers 4

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You're not actually "in PHP" when you're attempting to output it.

In other words, you have to open a PHP section to echo the variable:

<?php echo $image; ?>

or, with your image tag:

<img src="<?php echo $image; ?>" />
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2 Comments

@user2320375 Are you sure? If you say that $image contains an actual text value and you do <?php echo $image; ?>, it will work... period. Can you verify that $image has a value and that you've properly spelled the variable in all instances of using it?
@newfurniturey: ya im sure.... i tried this yesterday... but no use.... ya it has value
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It's because when you write $image into HTML textarea, it's treated as a string not as variable.

So, you should write the full image URL to your database, something like img\thumb\2.jpg and then read it to the browser.

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1 Comment

ya exactly ! its treated as string... i have to use this page multiple times. so again n again i cant put exact address... it will be cumbersome... so want to use script only..
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Use html_entity_decode Convert all HTML entities to their applicable characters

html_entity_decode($content);

Example

$b = html_entity_decode("I'll &quot;walk&quot; the &lt;b&gt;dog&lt;/b&gt; now");

echo $b; // I'll "walk" the <b>dog</b> now
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1 Comment

i need to insert content into table field "content" so i used htmlspecialcharacter() , without this it wont get inserted into table.. while inserting into table i want it to be encoded only...
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See when you are trying to input special characters like <, >, & etc. they are converted into their HTML formats like < is converted into &lt;, similarly > is converted into &gt;. Thats why when you are trying to insert < or > symbol in database it is inserting it like &lt; and &gt;. You shouldn't use them like this. But if you really need them you can replace &lt; with < and &gt; with > just before Insert query.

$qry = "INSERT INTO TEST (HEAD, CONTENT) VALUES (" . $head . ", " . $content . ")";
$qry = str_replace("&lt;", "<", $qry);
$qry = str_replace("&gt;", ">", $qry);

and then you can use $qry for insertion.

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