10

I would like to create a function that has optional arguments with default values

def my_function(a = nil, b=nil, c=500)

end

and call the function with the arguments I would like to specify only

my_function(b=100)

How do I accomplish this in Ruby 1.9.2?

3 Answers 3

29

Arguments are bound to parameters like this:

  1. As long as there are unbound mandatory parameters at the beginning of the parameter list, bind arguments left-to-right
  2. As long as there are unbound mandatory parameters at the end of the parameter list, bind arguments right-to-left
  3. Any leftover arguments are bound to optional parameters left-to-right
  4. Any leftover arguments are collected into an array and bound to the splat argument
  5. A block is wrapped up into a Proc and bound to the block argument
  6. If there are any unbound parameters or leftover arguments, raise an ArgumentError

Here's an example:

def foo(mand1, mand2, opt1=:opt1, opt2=:opt2, *splat, mand3, mand4, &block)
  p local_variables.map {|v| "#{v} = #{eval(v.to_s)}" }
end

foo 1, 2, 3
# ArgumentError: wrong number of arguments (3 for 4+)

foo 1, 2, 3, 4
# mand1 = 1
# mand2 = 2
# opt1 = opt1
# opt2 = opt2
# splat = []
# mand3 = 3
# mand4 = 4
# block = 

foo 1, 2, 3, 4, 5
# mand1 = 1
# mand2 = 2
# opt1 = 3
# opt2 = opt2
# splat = []
# mand3 = 4
# mand4 = 5
# block = 

foo 1, 2, 3, 4, 5, 6
# mand1 = 1
# mand2 = 2
# opt1 = 3
# opt2 = 4
# splat = []
# mand3 = 5
# mand4 = 6
# block = 

foo 1, 2, 3, 4, 5, 6, 7
# mand1 = 1
# mand2 = 2
# opt1 = 3
# opt2 = 4
# splat = [5]
# mand3 = 6
# mand4 = 7
# block = 

foo 1, 2, 3, 4, 5, 6, 7, 8 do end
# mand1 = 1
# mand2 = 2
# opt1 = 3
# opt2 = 4
# splat = [5, 6]
# mand3 = 7
# mand4 = 8
# block = #<Proc:0x007fdc732cb468@(pry):42>

So, as you can see both from step 3 above and from the example, you cannot do this, because optional parameters are bound left-to-right, but you want to specify the middle argument.

Note that this has implications on API design: you should design your parameter lists in such a way that the most "unstable" optional parameters, i.e. the ones that a user most likely wants to supply themselves, are furthest to the left.

Ruby 2.0 now has keyword arguments, which is exactly what you are looking for:

def foo(m1, m2, o1=:o1, o2=:o2, *s, m3, m4, key1: :key1, key2: :key2, **keys, &b)
  puts local_variables.map {|v| "#{v} = #{eval(v.to_s)}" }
end

foo 1, 2, 3
# ArgumentError: wrong number of arguments (3 for 4+)

foo 1, 2, 3, 4
# m1 = 1
# m2 = 2
# o1 = o1
# o2 = o2
# s = []
# m3 = 3
# m4 = 4
# key1 = key1
# key2 = key2
# b = 
# keys = {}

foo 1, 2, 3, 4, 5
# m1 = 1
# m2 = 2
# o1 = 3
# o2 = o2
# s = []
# m3 = 4
# m4 = 5
# key1 = key1
# key2 = key2
# b = 
# keys = {}

foo 1, 2, 3, 4, 5, 6
# m1 = 1
# m2 = 2
# o1 = 3
# o2 = 4
# s = []
# m3 = 5
# m4 = 6
# key1 = key1
# key2 = key2
# b = 
# keys = {}

foo 1, 2, 3, 4, 5, 6, 7
# m1 = 1
# m2 = 2
# o1 = 3
# o2 = 4
# s = [5]
# m3 = 6
# m4 = 7
# key1 = key1
# key2 = key2
# b = 
# keys = {}

foo 1, 2, 3, 4, 5, 6, 7, 8
# m1 = 1
# m2 = 2
# o1 = 3
# o2 = 4
# s = [5, 6]
# m3 = 7
# m4 = 8
# key1 = key1
# key2 = key2
# b = 
# keys = {}

foo 1, 2, 3, 4, 5, 6, 7, 8, key1: 9
# m1 = 1
# m2 = 2
# o1 = 3
# o2 = 4
# s = [5, 6]
# m3 = 7
# m4 = 8
# key1 = 9
# key2 = key2
# b = 
# keys = {}

foo 1, 2, 3, 4, 5, 6, 7, 8, key1: 9, key2: 10
# m1 = 1
# m2 = 2
# o1 = 3
# o2 = 4
# s = [5, 6]
# m3 = 7
# m4 = 8
# key1 = 9
# key2 = 10
# b = 
# keys = {}

foo 1, 2, 3, 4, 5, 6, 7, 8, key1: 9, key2: 10, key3: 11
# m1 = 1
# m2 = 2
# o1 = 3
# o2 = 4
# s = [5, 6]
# m3 = 7
# m4 = 8
# key1 = 9
# key2 = 10
# b = 
# keys = {:key3=>11}

foo 1, 2, 3, 4, 5, 6, 7, 8, key1: 9, key2: 10, key3: 11, key4: 12 do end
# m1 = 1
# m2 = 2
# o1 = 3
# o2 = 4
# s = [5, 6]
# m3 = 7
# m4 = 8
# key1 = 9
# key2 = 10
# b = #<Proc:0x007fdc75135a48@(pry):77>
# keys = {:key3=>11, key4=>12}
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Comments

8

You cannot do that (or something similar) in Ruby < 2.0. The best you could do is:

def my_function(h = {})
  h[:c] ||= 500
  # Use h[:a], h[:b], h[:c]
  ...
end

my_function(b: 100)

4 Comments

-1. This is wrong. You can have as many optional arguments as you want, and they don't have to be last. def foo(mand1, mand2, opt1=:opt1, opt2=:opt2, *splat, mand3, mand4, &block) p local_variables.map {|v| "#{v} = #{eval(v.to_s)}" } end is perfectly fine.
@JörgWMittag Right. I was wrong about that. I will remove that part.
@JörgWMittag I think that some older version of Ruby did require the arguments having defaults to be, if not last, at least after all "ordinary" arguments.
Ah, yes. It seems that Ruby 1.9 introduced the ability to default defaults before non-default arguments.
8

So you're trying to implement keyword arguments? This is supposed to be a new feature in Ruby 2.0, but you can try to mimic it in 1.9.x with a hash of arguments instead. Here's a post that discusses how you can accomplish that, which gives the following code sample:

def foo(options = {})
  options = {bar: 'bar'}.merge(options)
  puts "#{options[:bar]} #{options[:buz]}"
end

foo(buz: 'buz') # => 'bar buz'

2 Comments

Don't create answers that really only contain a link to an answer. WHEN that link breaks, will your answer be useful? Instead, summarize the pertinent part of that answer.
The link is broken

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