I need to check if the string provided by the user starts with abc and ends with de with 4 characters in between like
"abc<4 characters>de".
I tried using pattern ("^abc.*(4)de$")
But it fails for the 4 characters in middle. Is there any problem with pattern.
To say you need exactly four characters, you can use one of those:
"^abc.{4}de$"
"^abc....de$"
Change the () brackets with {}
^abc.{4}de$
which means that the matching word should start with abc and end with de and in between there should be excactly 4 characters.
A simpler solution is just to place a . between the start and the end pattern to describe that there should be exactly four characters:
^abc....de$
Use this regular expression :
^abc.{4}de$
.{4} is exactly what it seems : any character (.) exactly 4 times.
Modify RegEx to following
Pattern p = Pattern.compile("^abc.{4}de$");
Matcher m = p.matcher("abc11111de");
boolean b = m.matches();
System.out.println(b);
