I have a binary data file that contains 2d and 3d coordinates in such order:
uint32 numberOfUVvectors;
2Dvec uv[numberOfUVvectors];
uint32 numberOfPositionVectors;
3Dvec position[numberOfPositionVectors];
uint32 numberOfNormalVectors;
3Dvec normal[numberOfNormalVectors];
2Dvec and 3Dvec are structs composed from 2 and 3 floats respectively.
At first, I read all these values using the "usual" way:
in.read(reinterpret_cast<char *>(&num2d), sizeof(uint32));
2Dvectors.reserve(num2d); // It's for an std::vector<2DVec> 2Dvectors();
for (int i = 0; i < num2d; i++){
2Dvec 2Dvector;
in.read(reinterpret_cast<char *>(&2Dvector), sizeof(2DVec));
2Dvectors.push_back(2Dvector);
}
It worked fine, but it was painfully slow (there can be more than 200k entries in a file and with so many read calls, the hdd access became a bottleneck). I decided to read the entire file into a buffer at once:
in.seekg (0, in.end);
int length = in.tellg();
in.seekg (0, in.beg);
char * buffer = new char [length];
is.read (buffer,length);
The reading is way faster now, but here's the question: how to parse that char buffer back into integers and structs?