If you have subdocument arrays, Mongoose automatically creates ids for each one. Example:
{
_id: "mainId"
subDocArray: [
{
_id: "unwantedId",
field: "value"
},
{
_id: "unwantedId",
field: "value"
}
]
}
Is there a way to tell Mongoose to not create ids for objects within an array?
It's simple, you can define this in the subschema :
var mongoose = require("mongoose");
var subSchema = mongoose.Schema({
// your subschema content
}, { _id : false });
var schema = mongoose.Schema({
// schema content
subSchemaCollection : [subSchema]
});
var model = mongoose.model('tablename', schema);
{ _id: false }, both levels of sub-schema are without ids. Any way to work around this behavior?
{ _id : true } ?let studentSchema = new Schema({ studentId: { type: ObjectId, ref: Student.modelName }, performance: [performanceSchema] }, { _id: false }); to this: let studentSchema = new Schema({ _id: false, id: false, studentId: { type: ObjectId, ref: Student.modelName }, performance: [performanceSchema] }); and that stopped _id creation on the studentSchema but retained _id creation on the objects in the performance array of sub-documents. Not sure if both _id: false and id: false are needed.You can create sub-documents without schema and avoid _id. Just add _id: false to your subdocument declaration.
var schema = new mongoose.Schema({
field1: {
type: String
},
subdocArray: [{
_id: false,
field: { type: String }
}]
});
This will prevent the creation of an _id field in your subdoc.
Tested in Mongoose v5.9.10
v8.3.0. Tested it myself.Additionally, if you use an object literal syntax for specifying a sub-schema, you may also just add _id: false to supress it.
{
sub: {
property1: String,
property2: String,
_id: false
}
}
I'm using mongoose 4.6.3 and all I had to do was add _id: false in the schema, no need to make a subschema.
{
_id: ObjectId
subDocArray: [
{
_id: false,
field: "String"
}
]
}
_id is a field rather than a constraint._id = mongoose.Types.ObjectId(), would that _id be unique across collection then?You can use either of the one
var subSchema = mongoose.Schema({
//subschema fields
},{ _id : false });
or
var subSchema = mongoose.Schema({
//subschema content
_id : false
});
Check your mongoose version before using the second option
NestJS example for anyone looking for a solution with decorators
@Schema({_id: false})
export class MySubDocument {
@Prop()
id: string;
}
Below is some additional information from the Mongoose Schema Type definitions for id and _id:
/**
* Mongoose assigns each of your schemas an id virtual getter by default which returns the document's _id field
* cast to a string, or in the case of ObjectIds, its hexString.
*/
id?: boolean;
/**
* Mongoose assigns each of your schemas an _id field by default if one is not passed into the Schema
* constructor. The type assigned is an ObjectId to coincide with MongoDB's default behavior. If you
* don't want an _id added to your schema at all, you may disable it using this option.
*/
_id?: boolean;
If you want to use a predefined schema (with _id) as subdocument (without _id), you can do as follow in theory :
const sourceSchema = mongoose.Schema({
key : value
})
const subSourceSchema = sourceSchema.clone().set('_id',false);
But that didn't work for me. So I added that :
delete subSourceSchema.paths._id;
Now I can include subSourceSchema in my parent document without _id. I'm not sure this is the clean way to do it, but it work.
TypeError: Invalid schema configuration:
falseis not a valid type at pathid.
_id: { id: false },
If adding this line makes your app show the error message mentioned above, you might be using the newest mongoose 7 module versions.
To solve it, modify the mentioned line by adding an underscore _ before the id in the { _id: false } syntax on that line. So, that line should now look like this:
_id: { _id: false },
