Using Python + Selenium, how to find whether the page title contains a particular string?

Question

To assert the page title, I do not want to do a hard check but rather a soft one, something like a string pattern match on the page title. For this, here is an excerpt of my code which unfortunately is not working:

wait = WebDriverWait(self.driver, 15)
wait.until(lambda driver:self.driver.title.lower().startswith('Checkout'))
self.assertIn("Checkout", self.driver.title)

This is the exact title of the page: Checkout - HarXYZ

Can someone please point out where I am making a mistake? Is there any other way of asserting the page title through string pattern match?

falsetru · Accepted Answer · 2013-07-25 07:10:07Z

5

self.driver.title.lower().startswith('Checkout') will always return False, because Checkout contain uppercase letter C.

wait.until(lambda driver:self.driver.title.lower().startswith('checkout'))

answered Jul 25, 2013 at 7:10

falsetru

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2 Comments

Praveen Pandey Over a year ago

Thanks falsetru. It worked! Such a silly mistake!!! I have just one more doubt. Just like startswith(), do we have something like contains() or some other method for string match comparison?

falsetru Over a year ago

@Praveen, There is in operator. needle in haystack.

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