I don't know any Ruby and am reading some documentationon it now. A doubt I have just after reading about using code blocks and the "yield" keyword is whether it is possible to pass more than one code block to a function, and use both at will from within the called function.
4 Answers
You can pass only one block at once but blocks are actually Proc instances and you can pass as many instances you wish as parameters.
def mymethod(proc1, proc2, &block)
proc1.call
yield if block_given?
proc2.call
end
mymethod(Proc.new {}, Proc.new {}) do
# ...
end
However, it rarely makes sense.
4 Comments
fengb
Blocks aren't exactly procs. They have common usecases and syntaxes, but they have enough implementation differences to cause confusing behavior. It's a bit pedantic, but the scoping difference has bit me before.
Simone Carletti
@fengb I just made a test. gist.github.com/242746 Do you have some more documentation about the difference between Proc and block? Ruby is telling me a block is a Proc.
fengb
Blocks are implicitly "typecasted" to proc by using the &var syntax. But there are certain operations that behave differently when used as a block versus a proc. Long winded but comprehensive comparison: innig.net/software/ruby/closures-in-ruby.rb
Simone Carletti
Thanks. This is a long article, I'm going to crunch it in small pieces. :)
You can create Proc objects and pass around as many as you like.
I recommend reading this page to understand the subtleties of all different block- and closure-like constructs Ruby has.
Comments
You can use the call method rather than yield to handle two separate blocks passed in.
Here's how:
def mood(state, happy, sad )
if (state== :happy)
happy.call
else
sad.call
end
end
mood(:happy, Proc.new {puts 'yay!'} , Proc.new {puts 'boo!'})
mood(:sad, Proc.new {puts 'yay!'} , Proc.new {puts 'boo!'})
You can pass args with for example:
happy.call('very much')
arguments work just like you'd expect in blocks:
Proc.new {|amount| puts "yay #{amount} !"}