Check array for partial match (PHP) [duplicate]

Question

I have an array of filenames which I need to check against a code, for example

array("120_120_435645.jpg","150_150_312312.jpg","250_250_1232327.jpg");

the string is "312312" so it would match "150_150_312312.jpg" as it contains that string. If there are no matches at all within the search then flag the code as missing.

I tried in_array but this seems to any return true if it is an exact match, don't know if array_filter will do it wither...

Thanks for any advice...perhaps I have been staring at it too long and a coffee may help :)

The point is that you don't need a loop by using preg_grep. — Jeroen van den Broek
– Jeroen van den Broek, Commented Aug 20, 2013 at 15:58

Community · Accepted Answer · 2017-05-23 12:16:58Z

17

$filenames = array("120_120_435645.jpg","150_150_312312.jpg","250_250_1232327.jpg");
$matches = preg_grep("/312312/", $filenames);
print_r($matches);

Output:

Array
(
    [1] => 150_150_312312.jpg
)

Or, if you don't want to use regex, you can simply use strpos as suggested in this answer:

foreach ($filenames as $filename) {
    if (strpos($filename,'312312') !== false) {
    echo 'True';
    }
}

Demo!

edited May 23, 2017 at 12:16

CommunityBot

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answered Aug 20, 2013 at 15:45

Amal

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