Arrayfun problems in matlab

Question

I'm trying to do a simple speed test in Matlab. I want it to factor 3^a-2 for each a from 1 to 20. Might be I'm choosing too small numbers here to see any significant difference, but I'm stuck anyway.

I tried to write

n = [1:20]
m = 3.^n-1
arrayfun(factor,m)

this gives a "not enough input parameters" error. I though it made sense but apparently not. After looking at some examples of arrayfun and the manual, i also tried

arrayfun(@(m)factor(m), m)
arrayfun(@(m), factor(m), m)
arrayfun(@factor, m)

but none worked. What's the correct way to do it? And also if I do speed tests of this sort, will the results be cached so I will have to use different numbers if I do the test again?

P0W · Accepted Answer · 2013-09-28 11:55:49Z

1

Use this :

l=arrayfun(@factor,m, 'UniformOutput', false);

To access use :

l{1}, l{2}...etc

answered Sep 28, 2013 at 11:55

P0W

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3 Comments

user1661303 Over a year ago

Thanks. Will it calulate the factors all at once, or not until I write l{2}?

P0W Over a year ago

@user1661303 yes it will calculate all factors at once, you can check that by omitting the semi-colon at last. This will display cells of each elements

user1661303 Over a year ago

OK, thanks. Just one more question. What's the difference in this context of writing l(2) and l{2}? I notice the output is different.

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