php - Get hidden form field Value based on select box choice

Question

Sorry for my bad title!:) According to this question how can I check and store the appeared field's value With php and mysql;

assume that the form is something like this:

<form method="post" action="#">
    <select name="job" id="job" class="medium">
        <option selected="selected" value="-1">Please Select...</option>
        <option value="1">Job A</option>
        <option value="2">Job B</option>
        <option value="3">Job C</option>
        <option value="4">Job D</option>
        <option value="0">Other</option>
    </select>

    <div id="foo" style="display:none;">
        <input type="text" name="job_other" id="job_other" placeholder="If Other, please specify" value="" />
    </div>
    <div>
        <input type="submit" name="submit" id="submit" value="submit" />
    </div>
</form>

when selecting the "Other" option, "job_other" text field will appear.(handled by javascript) is my procedure true to check and get field in php like this:

<?php 
 $input['job'] = (isset($_POST['job']) && $_POST['job'] != '-1') ? $_POST['job'] : '';

 if ( $input['job'] != '' &&  $input['job'] == '0') {
    $input['job_other'] = (isset($_POST['job_other']) && $_POST['job_other'] != '' && $_POST['job_other'] == '0') ? $_POST['job_other'] : '';
 }

?>

By the way when the field appear, it will be Required. so how can I do this better?

if ( $input['job'] != '' && $input['job'] == '0') could be simplified by if($input['job'] == '0') : demo — Brewal
– Brewal, Commented Oct 1, 2013 at 14:06
Question title is fine but question contents I couldn't understand, could you please rephrase what you want? — Hanky Panky
– Hanky Panky, Commented Oct 1, 2013 at 14:07
I want to get the hidden field just when it appears in the form as a required field by php. — Akinak
– Akinak, Commented Oct 1, 2013 at 14:10
Oops, actually I messed up... You should test like so : if($input['job'] === '0') so it doesn't match false, 0 or FALSE. Demo — Brewal
– Brewal, Commented Oct 1, 2013 at 14:14

Rully · Accepted Answer · 2013-10-01 15:12:16Z

1

This would be sufficient:

<?php 
 $input['job'] = (isset($_POST['job'])) ? (int) $_POST['job'] : -1;

 $input['job_other'] = ( ($input['job'] == 0) && (isset($_POST['job_other'])) ) ? $_POST['job_other'] : '';
?>

Save the 'job' field as integer and 'job_other' as string / varchar.

edited Oct 1, 2013 at 15:12

answered Oct 1, 2013 at 14:52

Rully

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2 Comments

Akinak Over a year ago

what if user dont select "other" option? again I store the field as an empty string?

<?php   $input['job'] = (isset($_POST['job'])) ? (int) $_POST['job'] : -1;   if ( $input['job'] == 0) {     $input['job_other'] = (isset($_POST['job_other'])) ? $_POST['job_other'] : '';  } else {$input['job_other'] = '';} ?>

Rully Over a year ago

Yes, or use the revised solution :)

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