build an array of integers inside a for next loop vb.net

Question

i got this far ... my data string, "num_str" contains a set of ~10 numbers, each separated by a comma. the last part of the string is a blank entry, so i use '.Trim' to avoid an error

Dim i As Integer
        Dim m_data() As String
        m_data = num_str.Split(",")

        For i = 0 To UBound(m_data)
            If m_data(i).Trim.Length > 0 Then
                MsgBox(Convert.ToInt32(m_data(i).Trim))
            End If
        Next i

as you can see from the Msgbox, each of the numbers successfully pass through the loop.

where i am stuck is how to place all of the 'Convert.ToInt32(m_data(i).Trim)' numbers, which are now presumably integers, into an array.

how do i build an array of integers inside the For / Next loop so i can find MAX and MIN and LAST

TIA

Tim Schmelter · Accepted Answer · 2013-10-01 22:26:06Z

1

You just need to initialize the array with the zero-based indexer. You can deduce it's initial size from the size of the string():

Dim m_data = num_str.Split({","c}, StringSplitOptions.RemoveEmptyEntries)
Dim intArray(m_data.Length) As Int32

For i = 0 To m_data.Length - 1
    intArray(i) = Int32.Parse(m_data(i).Trim())
Next i

Note that i've also used the overload of String.Split which removes empty strings.

answered Oct 1, 2013 at 22:26

Tim Schmelter

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Comments

jcwrequests · Accepted Answer · 2013-10-01 22:39:57Z

0

This way is more concise using the Select LINQ Operator.

Dim arrayOfInts = num_str.
                Split({","c}, 
                StringSplitOptions.RemoveEmptyEntries).
                Select(Function(v) Int32.Parse(v.Trim()))

Dim minInt = arrayOfInts.Min()
Dim maxint = arrayOfInts.Max()

edited Oct 1, 2013 at 22:39

answered Oct 1, 2013 at 22:34

jcwrequests

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