PHP SESSION Array only storing in index 0

Question

Hey guys this is the code I am using

$ch="s1";
$_SESSION[$ch] = array();
$_SESSION[$ch][] = $_POST['t0'];
$_SESSION[$ch][] = $_POST['t1'];
$_SESSION[$ch][] = $_POST['t2'];
$_SESSION[$ch][] = $_POST['t3'];
$_SESSION[$ch][] = $_POST['t4'];
$_SESSION[$ch][] = $_POST['t5'];
$_SESSION[$ch][] = $_POST['t6'];

But when I am printing the session data on screen $_SESSION['s1'][0] is having all the data of all the other index, $_SESSION['s1'][1] to $_SESSION['s1'][6] are not displaying anything.

Here is the result for var_dump($_SESSION);

's1' => array (size=7) 
   0 => string 'All Purpose Horn Anvil A-1t1=Shipping Weight: 900gmst2=Price: € 5.00t3=Quantity: t4= t5=56t6=All Purpose Horn Anvil A-1 Shipping Weight: 900gms Price: € 5.00 Quantity: 56' (length=192) 
    1 => null 
    2 => null 
    3 => null 
    4 => null 
    5 => null 
    6 => null

For some reason the POST indexes i.e t0 to t6 are been shown in s1.

Done, I don't know why all the Post data are getting appended to the first index. — Ankur
– Ankur, Commented Oct 8, 2013 at 14:09
it would be nice if you could mark an answer as accepted. :) — Krimson
– Krimson, Commented Oct 9, 2013 at 19:22
Actually none of the replies are answering my question, it was a mistake in jquery which I posted below as the answer. :) — Ankur
– Ankur, Commented Oct 10, 2013 at 11:16

Piotr Müller · Accepted Answer · 2013-10-08 14:01:22Z

1

Propably you overwrite that data in other place or just do a mistake in printing.

$ch="s1";
$_SESSION[$ch] = array();
$_SESSION[$ch][] = mt_rand(1,200);
$_SESSION[$ch][] = mt_rand(1,200);
$_SESSION[$ch][] = mt_rand(1,200);
$_SESSION[$ch][] = mt_rand(1,200);
$_SESSION[$ch][] = mt_rand(1,200);
$_SESSION[$ch][] = mt_rand(1,200);
$_SESSION[$ch][] = mt_rand(1,200);
print_r( $_SESSION );

Output:

Array ( [s1] => Array ( [0] => 158 [1] => 145 [2] => 110 [3] => 139 [4] => 153 [5] => 183 [6] => 51 ) )

answered Oct 8, 2013 at 14:01

Piotr Müller

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2 Comments

Ankur Over a year ago

I don't understand, please give details.

Piotr Müller Over a year ago

The problem is not in code fragment that you have posted - the problem is in other place.

Ankur · Accepted Answer · 2013-10-08 14:32:25Z

1

It was a mistake in passing data to POST. In Jquery I was using this without the "&" between the variables, that was causing the problem.

var dataString = 't0=' + txt[0]+ '&t1='+ txt[1] + '&t2='+ txt[2] + '&t3='+ txt[3] + '&t4='+ txt[4] + '&t5='+ txt[5] + '&t6='+ temp;

answered Oct 8, 2013 at 14:32

Ankur

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Comments

sensorario · Accepted Answer · 2013-10-08 14:10:00Z

0

Try to add a dot before equal:

    $ch="s1";
    $_SESSION[$ch] = array();

    $_SESSION[$ch][] .= $_POST['t0'];
    $_SESSION[$ch][] .= $_POST['t1'];
    $_SESSION[$ch][] .= $_POST['t2'];
    $_SESSION[$ch][] .= $_POST['t3'];
    $_SESSION[$ch][] .= $_POST['t4'];
    $_SESSION[$ch][] .= $_POST['t5'];
    $_SESSION[$ch][] .= $_POST['t6'];

You can see this code working on this link (3v4l.org/8ZDi9):

<?php

    $ch="s1";
    $_SESSION[$ch] = array();

    $_SESSION[$ch][] .= 11;
    $_SESSION[$ch][] .= 22;

    var_dump($_SESSION);

edited Oct 8, 2013 at 14:10

answered Oct 8, 2013 at 14:02

sensorario

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4 Comments

Rolice Over a year ago

This seems to be wrong, empty [] means array_push (bit optimized one). There is no item to concatenate with in this moment.

Rolice Over a year ago

It will work if you have suppressed error reporting, because you concatenate 11 to undefined variable. PHP will allow you to do so, but however it cannot help the guy question, it will act the same way as without the ..

Kethryweryn Over a year ago

This also turns the integers into strings.

Rolice Over a year ago

I would bet on $str = (string) $integer.

Krimson · Accepted Answer · 2013-10-09 19:20:55Z

0

$ch="s1";
$_SESSION[$ch] = array();
$_SESSION[$ch][0] = $_POST['t0'];
$_SESSION[$ch][1] = $_POST['t1'];
$_SESSION[$ch][2] = $_POST['t2'];
$_SESSION[$ch][3] = $_POST['t3'];
$_SESSION[$ch][4] = $_POST['t4'];
$_SESSION[$ch][6] = $_POST['t5'];
$_SESSION[$ch][7] = $_POST['t6'];

Or better

$ch="s1";
$_SESSION[$ch] = array();


for ($i=0; $i<=6; $i++)
{
   $_SESSION[$ch][$i] = $_POST['t'.$i];
}

edited Oct 9, 2013 at 19:20

answered Oct 8, 2013 at 14:37

Krimson

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1 Comment

bksi Over a year ago

Fix this row: $_SESSION[$ch][6] = $_POST['t5'];

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