Removing borders from an image in Python

Question

Some videos have frames that have black strips like borders. I have to remove them from the frames. I came up with a crude solution:

import sys, cv2, numpy
import Image, scipy

filename = "snap.jpeg"

img = cv2.imread(filename)

def checkEqual(lst):
    return len(set(lst)) <= 1 ## <-- This is the maximum length of the set

def removeColumns(image):
    for col in range(image.shape[1]):
        for ch in range(3):
            try:
                checkEqual(image[:, col, ch].tolist())
            except IndexError:
                continue
            else:
                if checkEqual(image[:, col, ch].tolist()):
                    try:
                        image = numpy.delete(image, col, 1)
                    except IndexError:
                        continue
                    else:
                        pass
    return image

img2 = removeColumns(img)

print img.shape, img2.shape ## (480, 856, 3) (480, 705, 3)

Here I find the columns that have the same elements and all the videos that I have have black borders. But even if I increase the maximum length in the function checkEqual() from 1 to 20 or 40, the whole black strip is not deleted.

This is the original image: enter image description here

This is the image after running the program: enter image description here

Could anyone give suggestion for a better solution to this problem ? Thanks!

Dreaded semicolon · Accepted Answer · 2021-08-13 02:03:44Z

24

This problem was already solved in this answer.

from PIL import Image, ImageChops

im = Image.open('iI3ZE.jpg')

def trim(im):
    bg = Image.new(im.mode, im.size, im.getpixel((0,0)))
    diff = ImageChops.difference(im, bg)
    diff = ImageChops.add(diff, diff, 2.0, -100)
    bbox = diff.getbbox()
    if bbox:
        return im.crop(bbox)


trim(im).show()

I used Pillow instead of PIL:

pip install pillow

Results in:

enter image description here

edited Aug 13, 2021 at 2:03

Dreaded semicolon

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answered Oct 9, 2013 at 12:22

metakermit

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Comments

John Greenall · Accepted Answer · 2013-10-09 12:27:19Z

3

using opencv and numpy as in your attempt how about something like this:

im = cv2.imread(filename)
h,w,d = im.shape
#left limit
for i in range(w):
    if np.sum(im[:,i,:]) > 0:
        break
#right limit
for j in xrange(w-1,0,-1):
    if np.sum(im[:,j,:]) > 0:
        break

cropped = im[:,i:j+1,:].copy() # deep copy to get byte-aligned array needed for opencv

answered Oct 9, 2013 at 12:27

John Greenall

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1 Comment

Wolfgang Over a year ago

For me this solution worked best removing black border, whereby pixel values are not necessarily exactly zero - by replacing np.sum with np.mean and > 3. Needed a bit of fiddeling, but very good results (unlike with the other solutions). Thanks!!!

Steve Barnes · Accepted Answer · 2013-10-09 12:20:41Z

1

I think that you will find that the problem goes away if you work from the other side of the image, as you are checking the first column (col[0] - it's black so you delete it and the black col[1] becomes col[0] then you check the col[1] - skipping the new col[0]....

If you start from the max it would work or if you stay on any given col once you have deleted it. Alternatively you can make a list of which to delete, reverse it and then do the deletions.

answered Oct 9, 2013 at 12:20

Steve Barnes

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Comments

Kobi K · Accepted Answer · 2013-10-09 12:19:23Z

0

Why not calculate the frame and use PIL

from PIL import Image

img = Image.open('myImage.jpeg')
box = (50, 50, 100, 100)
area = img.crop(box)

answered Oct 9, 2013 at 12:19

Kobi K

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1 Comment

Monica Heddneck Over a year ago

Then what? Where's the save?

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