How to open URL by Desktop object in Java?

Question

I have a button to open a URL in browser:

URI uri = new URI("http://google.com/");
Desktop dt = Desktop.getDesktop();
dt.browse(uri.toURL()); // has error

but i get following error in last statement:

The method browse(URI) in the type Desktop is not applicable for the arguments (URL)

thanks for any suggestion.

Samiey Mehdi · Accepted Answer · 2013-10-15 07:31:16Z

3

Found solution:
1. Remove .toURL()
2. use try catch block

try
{
    URI uri = new URI("http://google.com/");
    Desktop dt = Desktop.getDesktop();
    dt.browse(uri);
}
catch(Exception ex){}

answered Oct 15, 2013 at 7:31

Samiey Mehdi

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1 Comment

James P. Over a year ago

Do avoid empty catch blocks like that. It's a cause of silent bugs which are hard to track.

RamonBoza · Accepted Answer · 2013-10-15 07:12:42Z

2

What it tells you is that you are sending an URL object while it expects an URI.

just change

dt.browse(uri.toURL()); // has error

to

dt.browse(uri); // has error

before being able to use Desktop, you have to consider if it is supported

if (Desktop.isDesktopSupported()) {
        desktop = Desktop.getDesktop();
        // now enable buttons for actions that are supported.
        enableSupportedActions();
}

and the enableSupportedActions

private void enableSupportedActions() {
    if (desktop.isSupported(Desktop.Action.BROWSE)) {
        txtBrowserURI.setEnabled(true);
        btnLaunchBrowser.setEnabled(true);
    }
}

that shows that you have to check also, if BROWSE action is also supported.

edited Oct 15, 2013 at 7:12

answered Oct 15, 2013 at 7:06

RamonBoza

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Comments

RayanFar · Accepted Answer · 2014-03-26 13:12:17Z

1

use some thing like this

try {Desktop.getDesktop().browse(new URI("http://www.google.com"));
} catch (Exception e) 
{JOptionPane.showMessageDialog(null,e);}
}

answered Mar 26, 2014 at 13:12

RayanFar

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