bad control character error in json parse

Question

When parsing a JSON object I am getting "bad control character" error in the Firebug console. There are lot of questions and solutions in this site; but I am unable to crack this issue. I believe I am doing something silly. Please point me to my mistake.

JS Fiddle: http://jsfiddle.net/Purus/Eqz2r/

If we change the json data to a plain text instead of html tags, it works.

Error:

SyntaxError: JSON.parse: bad control character in string literal
someVal = JSON.parse(sign);

NOTE:

The JSON data is obtained from a PHP function using json_encode function.
The json output looks valid in jsonlint

Below is the code I have used.

$(document).ready(function () {
   var sign = '{"data":"<br\/><br\/>----------<br \/>\r\nFrom Yahoo Team<br \/>\r\n<a href=\"http:\/\/localhost\/base\/1-yahoo-logo.jpg\" target=\"_blank\"><img style=\"padding: 5px;\" src=\"http:\/\/localhost\/plugins\/1-yahoo-logo.jpg\" height=\"120\" width=\"196\" \/><\/a>"}';

   someVal = JSON.parse(sign);
   $(".demo").append(someVal.data);
});

TimCodes.NET · Accepted Answer · 2013-10-24 18:28:41Z

9

You need to escape your escapes :)

Use double \\ instead of \

http://jsfiddle.net/Eqz2r/2/

answered Oct 24, 2013 at 18:28

TimCodes.NET

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6 Comments

Purus Over a year ago

Thanks. But how can I do that in PHP before passing on the JSON in JS.

TimCodes.NET Over a year ago

actually, replace on server side or js side I guess it doesn't matter?

Purus Over a year ago

Thats great news. I could not understand what to replace with what. In your fiddle, I see sign.replace("\n", "\n") which I could not make sense replacing same char by itself.

Purus Over a year ago

When I try sign.replace("\", "\\") it says illegal character. I am pretty new to JS. Please bear with me.

TimCodes.NET Over a year ago

that was carried over from your fiddle ;). Try doing it on the php side, i'm not familiar with php but you need to swap single slashes for double (try this i found: str_replace("\\", "\\\\", $data);)

|

Roope Hakulinen · Accepted Answer · 2015-04-24 21:08:52Z

4

var s= JsonString;
$.parseJSON(s.replace(/\s+/g,""));

edited Apr 24, 2015 at 21:08

Roope Hakulinen

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answered Jan 24, 2014 at 22:25

KNC

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Comments

Howard Renollet · Accepted Answer · 2013-11-19 14:54:00Z

2

The problem is the \r and \n. These need to be escaped as

\\r

and

\\n

in the JSON string

edited Nov 19, 2013 at 14:54

user2992935

answered Oct 24, 2013 at 18:32

Howard Renollet

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