what is wrong with this below code ? why it is printing size of array as zero?
function test() {
var arr = [];
for(var i = 0; i < 10; i++)
{
console.log('i ->' + i);
arr.push[i];
}
console.log('\n' + 'array length :' + arr.length);
}
--
Output:
i ->0
i ->1
i ->2
i ->3
i ->4
i ->5
i ->6
i ->7
i ->8
i ->9
array length :0
--
it is printing as zero(0)
push is a function.
You need to write arr.push(i) and not arr.push[i]. What you're doing in the latter is referring to arr.push as if it were an array, and then trying to access its ith subscript (or assuming that push is an object and trying to access a property that has the same value of i); it's effectively the same as writing a single line statement like so:
someArray[i];
Which doesn't really do anything.
Note: I have been bitten by this silly bug many times as well when I type too fast. ;)
Because .push[i] should be .push(i).
The reason you didn't get an error is that functions are objects in JavaScript, so you can legally get and set properties on functions.
What you were doing was fetching the the i property from the Array.prototype.push method (which will be undefiend).
console.log(arr.push[i]); // undefined
Probably worth noting that jsHint would catch this for you.
[]... tryarr.push(i);.