jquery $.when $.then issue

Question

I try to use $.when with ajax calls, where on of the calls won't always be called, how can I achieve this. I've been trying to hack around it

var renderThis;
$.when($.post("/blabla", function(data){
            renderThis = data;
        }),
        function(){
            if(another){
                return $.post("/blabla");
            }
            else{
                return true;
            }
        })
        .then(function(){
            render(renderThis)
        });

but what I see is that the $.then() isn't called in a deferred manner but is called instantly.

any ideas?

Robert Koritnik · Accepted Answer · 2013-11-05 11:39:28Z

5

.when needs function results instead of function references. Your second parameter to .when is function reference. Try using an immediately executing function instead:

$.when(
    $.post("/blabla"),
    (function() {
        if(another){
            return $.post("/blabla");
        }
        else{
            return true;
        }
    })())
.then(
    function(data1, data2){
        render(data1);
    });

As you can see I've also consolidated first success function to be process on when instead providing it inline with .post call.

edited Nov 5, 2013 at 11:39

answered Nov 5, 2013 at 11:23

Robert Koritnik

105k57 gold badges286 silver badges415 bronze badges

Sign up to request clarification or add additional context in comments.

Comments

Arun P Johny · Accepted Answer · 2013-11-05 11:17:36Z

2

Try

var requests = [$.post("/blabla")];
if (another) {
    requests.push($.post("/blabla"))
}
$.when.apply($, requests).then(function (data1) {
    render(data1[0])
});

answered Nov 5, 2013 at 11:17

Arun P Johny

389k68 gold badges532 silver badges532 bronze badges

Collectives™ on Stack Overflow

jquery $.when $.then issue

2 Answers 2

Comments

Comments

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

2 Answers 2

Comments

Comments

Your Answer

Sign up or log in

Post as a guest

Related