Regex Pattern for filtering URLs

Question

I'm trying to filter a URL using regex and now I have added new portion to the URL so existing regex script won't work.

  location ~ ^/p/(?<secure>[\w\-=]+,\d+)(?<file>/.*)$

I get $secure , $file values, now I need to get $user as well.

Old URL structure:

 /p/uwoT4ccBKjBryHxQNrwRzA,1385726761/test.zip

New URL structure:

 /p/uwoT4ccBKjBryHxQNrwRzA,1385726761,USER/test.zip

I've added ,USER portion to the new URL, how do you do this in regex?

Fabien Sa · Accepted Answer · 2013-11-17 22:46:18Z

1

Try this regex:

location ~ ^/p/(?<secure>[\w\-=]+,\d+),(?<user>[^/]+)(?<file>/.*)$

$secure, $file and $user

answered Nov 17, 2013 at 22:35

Fabien Sa

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2 Comments

Great, THANKS! btw How do you do it?

, is outside (...) thus it will not be match.