I need to change it into :
$arr['id']=1;
$arr['type']=2;
-
Possible duplicate of How to get parameters from this URL string?nhahtdh– nhahtdh2015-10-26 05:00:15 +00:00Commented Oct 26, 2015 at 5:00
Add a comment
|
5 Answers
Use: parse_str().
void parse_str(string $str [, array &$arr])
Parses str as if it were the query string passed via a URL and sets variables in the current scope.
Example:
<?php
$str = "first=value&arr[]=foo+bar&arr[]=baz";
parse_str($str);
echo $first; // value
echo $arr[0]; // foo bar
echo $arr[1]; // baz
parse_str($str, $output);
echo $output['first']; // value
echo $output['arr'][0]; // foo bar
echo $output['arr'][1]; // baz
?>
1 Comment
nhahtdh
This answer should have a warning for the first method, since it will overwrite variables in global scope.
Assuming you want to parse what looks like a query string, just use parse_str():
$input = 'id=1&type=2';
$out = array();
parse_str($input, $out);
print_r($out);
Output:
Array
(
[id] => 1
[type] => 2
)
You can optionally not pass in the second parameter and parse_str() will instead inject the variables into the current scope. Don't do this in the global scope. And I might argue don't do it at all. It's for the same reason that register_globals() is bad.
$arr = array();
$values = explode("&",$string);
foreach ($values as $value)
{
array_push($arr,explode("=",$value));
}
Comments
Use parse_str() with the second argument, like this:
$str = 'id=1&type=2';
parse_str($str, $arr);
$arr will then contain:
Array
(
[id] => 1
[type] => 2
)
