How to iterate over an array within an object if the object meets certain conditions?

Question

I want to achieve the functionality of:

Iterate over the array in the object where k1's value is woo hoo!.

The following works but i'm not sure it's the best way because I think it would need to loop over each object before it found a match.

Array

myArray = [{"k1": "woo hoo!", "k2": ["k2_1","k2_2","k2_3"], "k3": ["k3_v1"]},{"k1": "boo", "k2": ["k2_v1"], "k3": ["k3_v1"]}]

jQuery

$.each(myArray, function (obj, v) {
    $.each(v.k2, function (i, value) {
        if (v.k1 == "woo hoo!") {
            alert(value);
        }
    });
});

The following contains this example as well as a few other commented out examples I have used to understand $.each more.

http://jsfiddle.net/rwone/MnASV/5/

don't use alert for debugging use console.log() - jsfiddle.net/arunpjohny/PPrxZ/1 — Arun P Johny
– Arun P Johny, Commented Jan 9, 2014 at 10:48

Arun P Johny · Accepted Answer · 2014-01-09 10:57:17Z

4

The only change you have to do is to move teh if condition out of the second loop.

In your case the k1 belongs to the outer object, but you are iterating through the second loop even of the value is not matching that can be avoided by checking it before.

// iterate over array within each object
$.each(myArray_1, function (obj, v) {
    if (v.k1 == "woo hoo!") {
        $.each(v.k2, function (i, value) {
            console.log(value);
        });
    }
});

Demo: Fiddle

edited Jan 9, 2014 at 10:57

answered Jan 9, 2014 at 10:50

Arun P Johny

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4 Comments

user1063287 Over a year ago

If there were many objects in the top level array, it seems it would need to iterate over each one and then perform the actions associated with the matching if condition. I was wondering if there was a quicker and more direct way to define at the top level "only iterate over an object with this certain property?". So something like iterate over this where foo == bar?

user1063287 Over a year ago

Your response has gotten several upvotes whilst I was writing my comment so I am guessing not, thanks for the answer - can accept in 3 minutes.

Arun P Johny Over a year ago

@user1063287 AFAIK there is no property like that... you can look at Array.filter() even that iterates through each element to find whether it satisfies the condition

Arun P Johny Over a year ago

@user1063287 don't always trust the upvotes!!! or for the matter downvotes... there could be another solution that I'm not aware of....

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