ASP.NET MVC3 can't bind a decimal field from a TextBoxFor to my Model

Question

This is probably a dummy question, but I'm stuck with a problem I can't resolve by myself.

I'm working on an ASP.NET MVC3 project. For some reason, on a particular Create page, a decimal field is not binded on the model when the page is validated and I can't understand why.
Here is my code :

@model ModelA

/*some TextBoxFor or others DropDownListFor, all of them working well*/

@Html.TextBoxFor(m => m.ModelB.ModelC.MyField, new { @id = "txtMyField" })

When I validate the page, the model ModelA is correctly filled EXCEPT for this particular field MyField. Others fields are OK, for exemple :

@Html.TextBoxFor(m => m.ModelB.AnotherField, new { @id = "txtAnotherField" })

perfecly works, and others properties of ModelB are correctly filled.

My models

ModelA contains a property of type ModelB called ModelB.
ModelB contains a property of type ModelC called ModelC.
ModelC contains a property called MyField. (I'll probably add one or two more in the future). This field is a decimal field, without any DataAnnotation or anything.

public decimal MyField { get; set; }

By the way, when in my browser's console I request

$('#txtMyField').val()

it displays the good value, for example 12.54.

What I tried

Change this decimal field to a float type, the problem is the same.
Put it in an EditorFor instead of a TextBoxFor, the problem is the same.
Put the field MyField in ModelB. The only ModelB's property to 0 is MyField.

Why is this field a rebel ? I probably do something wrong, but I can't understand where... Can someone explain me where is my mistake ?
Thank you !

Have you tried renaming the property? Just to discard for example a collision with a route parameter — Daniel J.G.
– Daniel J.G., Commented Jan 18, 2014 at 18:13

user2687153 · Accepted Answer · 2014-01-18 19:21:50Z

2

Ok, so here is the solution :

A "correct" decimal value looks like 45.68 with a . as a separator.
But the application is a non-English application, and the separator need to be a ,. By default, 45,68 is not a correct number. So I added this piece of code :

jQuery.extend(jQuery.validator.methods, {
    number: function (value, element) {
        return this.optional(element) || /^-?(?:\d+|\d{1,3}(?:\.\d{3})+)(?:,\d+)?$/.test(value);
    }
});

and 45,68 is recognized as a correct number.

answered Jan 18, 2014 at 19:21

user2687153

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1 Comment

omnisius Over a year ago

Easiest & best way to solve the problem ! THANK YOU A LOT !

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