I am trying to make the program print out "OK" for as long as i enter 'y' as a choice at the end, but it is not looping, it just prints out "OK" and ends the program even if i enter a 'y' at the end. Please help.
#include <stdio.h>
int main()
{
char c = 'y';
while (c == 'y')
{
printf_s("OK\n");
scanf_s("%c", &c);
if (c != 'y')
{
break;
}
}
return 0;
}
On first iteration when you press Enter key then a newline character \n is passed to the input along with y. On second iteration scanf_s reads \n.
Change
scanf_s("%c", &c);
to
scanf_s(" %c", &c);
^Notice the space before %c
A space before %c specifier can consume any number of white-space characters.
scanf_s method requires that all storage locations be followed with an explicit size.Change the scanf_s line as follows
scanf_s("%c", &c, 1);
This extra parameter is specifying the size of the c argument. Plain old scanf doesn't require this argument but the versions ending with _s do
Also the if block with the break statement is unnecessary because the conditional on the while loop effectively does the same thing. It could be written as follows
while (c == 'y')
{
printf_s("OK\n");
scanf_s("%c", &c, 1);
}
OK I used scanf instead of scanf_s, that solved the problem, thanks everyone.
scanf_s see my answer as it corrects the usage of htis APIYou are wrong with scanf
if you use like this u will see it is working ..
#include <stdio.h>
int main()
{
int c = 1;
while (c == 1)
{
printf_s("OK\n");
scanf_s("%d", &c);
if (c != 1)
{
printf_s("hello\n");
continue;
}
}
return 0;
}
Put a space before %c to skip whitespace.
fflush(stdin)before scanfscanf_sreference.