How to form PHP curl request for the following command line?

Question

Can someone help me to form this commndline request in PHP ?

$ curl -u [USER:PASSWORD] https://subs.pinpayments.com/api/v4/meresheep/subscribers/7388.xml

I have tried the following and getting only 'false' returned...

 // Query the user to pin payments for the details...
 $curl_url = "https://subs.pinpayments.com/api/v4/xyz-site/subscribers/32.xml";

 //open connection
 $ch = curl_init();

 //set the url, number of POST vars, POST data
 curl_setopt($ch, CURLOPT_URL, $url);
 curl_setopt($ch, CURLOPT_RETURNTRANSFER,1);
 curl_setopt($ch, CURLOPT_SSL_VERIFYPEER, false);
 curl_setopt($ch, CURLOPT_HTTPHEADER, array('Authorization: -u [USER:PASSWORD]'));

 //execute post
 $result = curl_exec($ch);
 curl_close($ch);

David Hancock · Accepted Answer · 2014-02-18 09:10:12Z

1

You need to change the CURLOPT_HTTPHEADER line:

curl_setopt($data, CURLOPT_HTTPHEADER, array(
    'Authorization: Basic ' . base64_encode('username:password')
));

edited Feb 18, 2014 at 9:10

answered Feb 18, 2014 at 9:04

David Hancock

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2 Comments

user3322546 Over a year ago

Hello David, Thanks for your reply... i tried in that way too... it is returning 'false' only... But when i access the URL via browser... it asks for username & password and when i entered the username mentioned above and hit enter and it shows me the proper output i wanted on screen... The funniest thing is the same CURL code is working perfectly in my localhost. Is there any additional param that i may have to pass along ?

David Hancock Over a year ago

You could try outputting the error with echo curl_error($ch); after the curl_exec() line.

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