reading numbers into an array in ruby

Question

I'm trying to read numbers from a txt file into an array in ruby with some conditions. The text file input looks like this:

1 2 3 4
5 6 7 8
9;10 11 12

What I want to do is read the numbers up to ';', store them in array, execute a method on that array, and then clear the array and start reading from the semicolon again. Here you can see the execution of the program with the input seen above:

read [1,2,3,4,5,6,7,8,9] -> Execute method X -> [] Clear array -> [10 11 12] -> execute method X...

I think a variation of the following code would do the trick, but I don't know enough ruby to do this myself.

 a = []
 File.open('names.txt') do |f|
   f.each_line do |line|
     a << line.split.map(&:to_i)
   end
 end

Thanks for your help! This is for curiosity, not an assignment or anything else. I'm trying to build ruby skills by doing simple things.

Doon · Accepted Answer · 2014-02-27 00:46:15Z

3

you can do something like this.

f = File.read 'names.txt' 
f.split(';').each  do |set|
  method_x(set.split.map(&:to_i))
end

This assumes method_x takes an array as an arg.

edited Feb 27, 2014 at 0:46

answered Feb 26, 2014 at 17:44

Doon

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Comments

Arup Rakshit · Accepted Answer · 2014-02-26 18:07:22Z

3

I would do as below :

File.readlines('a.txt',';').each do |string|
  ary = string.scan(/\d+/).map(&:to_i)
  method_x(ary)
end

You can put the line separator as ;, as per the documentation readlines(name, sep=$/ [, open_args]) .

Reads the entire file specified by name as individual lines, and returns those lines in an array. Lines are separated by sep.

edited Feb 26, 2014 at 18:07

answered Feb 26, 2014 at 18:01

Arup Rakshit

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Comments

xlembouras · Accepted Answer · 2014-02-26 17:50:35Z

0

File.read('names.txt').split(';').each { |x| the_function(x.split.map(&:to_i)) }

where the_function is your desired function

answered Feb 26, 2014 at 17:50

xlembouras

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