Array is ignoring Null as a value

Question

I have the code:

for (int i = 0; i < directory.length; i++) {
    if (directory[i].contains (number)) {
        if (directory[i+1] == null){
            directory[i] = null;
        }
        else {
            for (int k=i; k<directory.length; k++){
                System.out.println(directory[k]);
                System.out.println(directory[k+1]);
                if (directory[i+1] != null){
                    directory[k] = directory[k+1];
                    System.out.println(directory[k]);
                }

The important bit i think is "if (directory[i+1] != null){" what i am using is an array and i am trying to find if the next element is not null then do the code. However, even if the next value is null it does it anyway. Any suggestions?

Thank you.

Sorry for not making the question clear, I have fixed the question now :) — user3006216
– user3006216, Commented Feb 27, 2014 at 20:55
I think you'd get an array index out of range error on the last iteration of the i loop, no? — Mike Christensen
– Mike Christensen, Commented Feb 27, 2014 at 21:00
What is the code supposed to do, and what is it not doing as expected? — Joffrey
– Joffrey, Commented Feb 27, 2014 at 21:04

aliteralmind · Accepted Answer · 2014-02-27 21:01:45Z

1

Your problem is that you are not using the loop-index in your loop. You're only testing the initial value, over and over again.

This

if (directory[i+1] != null){

should be this

if (directory[k+1] != null){

answered Feb 27, 2014 at 21:01

aliteralmind

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d4nk1337sauce · Accepted Answer · 2014-02-27 21:04:06Z

1

the next value of directory[i+1] is never going to be null @"if (directory[i+1] != null){" because before the else statment you check to see if directory[i+1] == null

my guess is a small typo in iteration maybe you ment directory[k+1]?

answered Feb 27, 2014 at 21:04

d4nk1337sauce

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