C++ Exception Handling In Base Class

Question

Supposing I have some general Application class definition which contains:

class Application{
    public:
    void Run(){
        try{
            ....
        }catch(const Exception& ex){
            ....
        }
}

Now supposing I inherit Application from class App1:

class App1: public Application{
    void Run(){
        Application::Run();
        throw ex;
    }
}

Is there a way to catch the exception in the base class? I tried the above and it doesn't work.

Slava · Accepted Answer · 2014-03-12 04:43:50Z

2

Using virtual function, like this:

    class Application{
    public:
    virtual void DoRun() {
    ....
    }
    void Run(){
        try{
            DoRun();
        }catch(const Exception& ex){
            ....
        }
}

class App1: public Application{
    virtual void DoRun() {
        Application::DoRun();
        throw ex;
    }
}

answered Mar 12, 2014 at 4:43

Slava

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1 Comment

aschepler Over a year ago

I would make DoRun protected, to emphasize that Run is the one outside code should be using.

R Sahu · Accepted Answer · 2014-03-12 04:39:22Z

0

No, you can't. By the time you throw ex; in App1:Run(), Application::Run() has already finished running.

answered Mar 12, 2014 at 4:39

R Sahu

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