Passing arguments to the generic views Django queryset

Question

I would like to make a queryset on a generic view in this way:

 category_info = {
      'queryset' : ModelObject.objects.filter(category=category_id)
 }

where the category_id will be stated on the URL

 (r'^category/(?P<category_id>\d+)$', 'object_list', category_info )

But I don't know how to take the data from the URL and pass it to the category info...

Wladimir Palant · Accepted Answer · 2012-06-09 09:09:10Z

3

You'll have to define your own view and return the generic view from within:

urls.py:

(r'^category/(?P<category_id>\d+)$', 'myapp.views.category_list')

myapp/views.py

from django.views.generic.list_detail import object_list
def category_list(request, category_id):
    queryset = ModelObject.objects.filter(category=category_id)
    return object_list(request, queryset=queryset)

You can also customise the generic view further, using the parameters mentioned in the documentation. (You may like to also verify that the category exists, throwing a 404 when it doesn't)

edited Jun 9, 2012 at 9:09

Wladimir Palant

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answered Feb 10, 2010 at 13:06

Will Hardy

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1 Comment

Khelben Over a year ago

I needed also to add the request parameter, this way: return object_list(request, queryset=queryset)

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