Render different static folder based on url request

Question

Using Flask, I can render different templates based on the url. For example :

http://example.com/site1/ ; will render templates/site1/{htmls}
http://example.com/site2/ ; will render templates/site2/{htmls}

This works really great with jinja_loader and a custom Loader, but now I'm stuck with the static files.

The static files depends on the template, so they are located in templates/static/site{0-9}, but of course, I cannot set a jinja_loader on the static_folder parameter because it's not related to Jinja but to Flask.

How can I render the correct static folder based on the current URL?

As an example, here's the loaded code:

Flask(app_name,
        static_url_path = '/public',
        static_folder = os.path.join(os.path.dirname(os.path.abspath(__file__)), 'templates/static')
    )

and in templates/static, I have :

static/
    site1/
        css/
        js/
        images/
    site2/
        css/
        js/
        images/
    etc...

I'm not sure what you are asking. Can you provide some URLs and how they should map to actual files? — Martijn Pieters
– Martijn Pieters, Commented Mar 17, 2014 at 11:42
And your templates are using url_for('static', 'site1/css/...'), etc. to generate the correct URLs already? What is the exact problem here? — Martijn Pieters
– Martijn Pieters, Commented Mar 17, 2014 at 12:06
No, my templates uses {{url_for('static', filename='css/...')}}. Ideally, I would modify where Flask search for the static files when rendering /public/css/..., to search not in /templates/static/css/..., but in /templates/static/site1/css/... — Cyril N.
– Cyril N., Commented Mar 17, 2014 at 12:13

Martijn Pieters · Accepted Answer · 2014-03-17 12:31:33Z

You either have to use explicit paths in your static views:

url_for('static', filename='site1/css/...')

where site1 could be taken from request.path.split('/', 1)[0]:

url_for('static', filename='{}/css/...'.format(request.path.split('/', 1)[0]))

You could create a custom static view:

from flask import request, send_from_directory, current_app, safe_join
import os.path

@app.route('/<site>/static/<path:filename>')
def per_site_static(site, filename):
    if site is None:
        # pick site from the URL; only works if there is a `/site/` first element.
        site = request.path.split('/')[0]
    static_folder = safe_join(current_app.static_folder, site)
    cache_timeout = current_app.get_send_file_max_age(filename)
    return send_from_directory(static_folder, filename,
                               cache_timeout=cache_timeout)

Then use url_for() to generate urls:

{{ url_for('per_site_static', site=None, filename='css/...') }}

Cyril N. · Accepted Answer · 2014-03-17 12:34:58Z

0

An other interesting alternative is the following :

class GenericStaticFlask(Flask):
    def send_static_file(self, filename):
        # g.site contains the name of the template path for siteX
        return super(GenericStaticFlask, self).send_static_file("%s/%s" % (g.site, filename))

app = GenericStaticFlask(app_name,
    static_url_path = '/public',
    static_folder = os.path.join(os.path.dirname(os.path.abspath(__file__)), 'templates/static')
)

answered Mar 17, 2014 at 12:34

Cyril N.

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