Randomizing Numbers without repeating it in C#

Question

I want to randomize 9 numbers so random number in each trail would be different of number in previous attempt... here is my code

            Random num1random = new Random();
        label1.Text = num1random.Next(1, 9).ToString();
        label2.Text = num1random.Next(1, 9).ToString();
        label3.Text = num1random.Next(1, 9).ToString();
        label4.Text = num1random.Next(1, 9).ToString();
        label5.Text = num1random.Next(1, 9).ToString();
        label6.Text = num1random.Next(1, 9).ToString();
        label7.Text = num1random.Next(1, 9).ToString();
        label8.Text = num1random.Next(1, 9).ToString();
        label9.Text = num1random.Next(1, 9).ToString();

there are many, many ways to randomise a set of integers. you might find some help here : stackoverflow.com/questions/375351/… — Timothy Groote
– Timothy Groote, Commented Mar 24, 2014 at 13:05

Rik · Accepted Answer · 2014-03-24 13:11:08Z

2

You don't really want 9 random numbers, you really want the numbers from 1 to 9 in a random order:

Random r = new Random();
var numbers = Enumerable.Range(1,9) // create a sequence of the integers 1 through 9
    .OrderBy(x => r.Next()) // randomize the order
    .ToArray(); // turn the sequence into an array.

// assign the numbers to the labels
label1.Text = numbers[0];
...
label9.Text = numbers[8];

answered Mar 24, 2014 at 13:11

Rik

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Ufuk Hacıoğulları · Accepted Answer · 2014-03-24 13:14:50Z

2

Random.Next is not guaranteed to return 9 distinct values. You should create the value list, then shuffle it.

Random num1random = new Random();
var numbers = Enumerable.Range(1, 9).OrderBy(item => num1random.Next()).ToList();
label1.Text = numbers[0].ToString();
//other labels

edited Mar 24, 2014 at 13:14

answered Mar 24, 2014 at 13:06

Ufuk Hacıoğulları

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2 Comments

Marc Gravell Over a year ago

I'd have probably have gone with item => num1random.Next(), but: sure

Ufuk Hacıoğulları Over a year ago

@MarcGravell That would make ordering 'more random' right?

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