Getting the value of a cygwin environment variable from a windows script

Question

I have a Windows batch script (to be honest, it's a Groovy script). In this script I determine the root directory of a Cygwin installation. The next step is to find out the current user and home directory. In Cygwin this would be just a

echo $HOME
#=> /home/Christian

What comes pretty close to my problem is the following question: Get results of command from Cygwin in Batch. I would like to execute something like this:

"C:\cygwin[64]\bin\bash[64].exe" "echo $HOME"

However I receive a

#=> /usr/bin/bash[64]: echo $HOME: No such file or directory

This is because bash is expecting a script file and I want to execute a single command. How can this be done? Is there a possibility without putting the command in a script file?

My goal is to get the Windows path to the current users home directory so that I can iterate over this directory from a Windows script.

Community · Accepted Answer · 2017-05-23 12:31:32Z

0

The correct option to issue a single command is -c, and before you need to perform a login with --login.

C:\>c:\cygwin64\bin\bash.exe --login -c "cygpath -w $HOME"
#=> C:\cygwin64\home\Christian

I found the answer here.

edited May 23, 2017 at 12:31

CommunityBot

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answered Mar 25, 2014 at 19:05

ChrLipp

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