Suppose, I have this string:
$string = "Hello! 123 How Are You? 456";
I want to set variable $int to $int = 123456;
How do I do it?
Example 2:
$string = "12,456";
Required:
$num = 12456;
Thank you!
5 Answers
Correct variant will be:
$string = "Hello! 123 How Are You? 456";
$int = intval(preg_replace('/[^0-9]+/', '', $string), 10);
5 Comments
Bangash
Now you check your code for string "hello 0123"... :)
Iłya Bursov
@ArifHussain yes, it works for 0123 and provides proper decimal 123, as expected
Bangash
@Lashane , so in that case Shankar's code is also correct, which you commented on.
Mike Doe
This code will malform large numbers, for example
abc12345678901234556782312312323123123131232Iłya Bursov
@mike php by nature cannot work with such big numbers, you need special library for this
You can use this method to select only digit present in your text
function returnDecimal($text) {
$tmp = "";
for($text as $key => $val) {
if($val >= 0 && $val <= 9){
$tmp .= $val
}
}
return $tmp;
}
answered Mar 29, 2014 at 7:27
Fopa Léon Constantin
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1 Comment
Mike Doe
Inefficient and slow.
Use this regular expression !\d!
<?php
$string = "Hello! 123 How Are You? 456";
preg_match_all('!\d!', $string, $matches);
echo (int)implode('',$matches[0]);
answered Mar 29, 2014 at 7:25
Shankar Narayana Damodaran
68.6k43 gold badges102 silver badges129 bronze badges
5 Comments
Shankar Narayana Damodaran
A
0 before a number is not required.
Helpful
Shankar, I think what Lashane is getting at is that (int) will cast that as octal if it's prefaced by a 0. Or am I completely off?
Iłya Bursov
@Helpful you're right, you cannot just use (int) to convert string to number in php
Shankar Narayana Damodaran
@Lashane, You are not getting it, the regex grabs the numbers from the string , and casting it to
int is not going to making it as octal.Iłya Bursov
@ShankarDamodaran yes, I've mistaken with javascript where you 0 prefixed numbers will be supposed as octal
You can use the below:
$array = [];
preg_match_all('/-?\d+(?:\.\d+)?+/', $string, $array);
Where $string is the entered string and $array is where each number(not digit!,including also negative values!) is loaded and available for different more operations.
Comments
<?php
$string = "ABC100";
preg_match_all('!\d+!', $string, $matches);
$number = $matches[0][0];
echo $number;
?>
Output: 100
1 Comment
mickmackusa
This code-only answer provides no new value to this page or Stack Overflow. Please only answer when you have something unique and valuable to add to the page. Worse, it only displays the first of all matches.
$int = preg_replace('/\D+/', '', $string);