91

I want to get all classes inside a namespace. I have something like this:

#File: MyClass1.php
namespace MyNamespace;

class MyClass1() { ... }

#File: MyClass2.php
namespace MyNamespace;

class MyClass2() { ... }

#Any number of files and classes with MyNamespace may be specified.

#File: ClassHandler.php
namespace SomethingElse;
use MyNamespace as Classes;

class ClassHandler {
    public function getAllClasses() {
        // Here I want every classes declared inside MyNamespace.
    }
}

I tried get_declared_classes() inside getAllClasses() but MyClass1 and MyClass2 were not in the list.

How could I do that?

0

15 Answers 15

58

Update: Since this answer became somewhat popular, I've created a packagist package to simplify things. It contains basically what I've described here, without the need to add the class yourself or configure the $appRoot manually. It may eventually support more than just PSR-4.

That package can be found here: haydenpierce/class-finder.

$ composer require haydenpierce/class-finder

See more info in the README file.


I wasn't happy with any of the solutions here so I ended up building my class to handle this. This solution requires that you are:

  • Using Composer
  • Using PSR-4

In a nutshell, this class attempts to figure out where the classes actually live on your filesystem based on the namespaces you've defined in composer.json. For instance, classes defined in the namespace Backup\Test are found in /home/hpierce/BackupApplicationRoot/src/Test. This can be trusted because mapping a directory structure to namespace is required by PSR-4:

The contiguous sub-namespace names after the "namespace prefix" correspond to a subdirectory within a "base directory", in which the namespace separators represent directory separators. The subdirectory name MUST match the case of the sub-namespace names.

You may need to adjust appRoot to point to the directory that contains composer.json.

<?php    
namespace Backup\Util;

class ClassFinder
{
    //This value should be the directory that contains composer.json
    const appRoot = __DIR__ . "/../../";

    public static function getClassesInNamespace($namespace)
    {
        $files = scandir(self::getNamespaceDirectory($namespace));

        $classes = array_map(function($file) use ($namespace){
            return $namespace . '\\' . str_replace('.php', '', $file);
        }, $files);

        return array_filter($classes, function($possibleClass){
            return class_exists($possibleClass);
        });
    }

    private static function getDefinedNamespaces()
    {
        $composerJsonPath = self::appRoot . 'composer.json';
        $composerConfig = json_decode(file_get_contents($composerJsonPath));

        return (array) $composerConfig->autoload->{'psr-4'};
    }

    private static function getNamespaceDirectory($namespace)
    {
        $composerNamespaces = self::getDefinedNamespaces();

        $namespaceFragments = explode('\\', $namespace);
        $undefinedNamespaceFragments = [];

        while($namespaceFragments) {
            $possibleNamespace = implode('\\', $namespaceFragments) . '\\';

            if(array_key_exists($possibleNamespace, $composerNamespaces)){
                return realpath(self::appRoot . $composerNamespaces[$possibleNamespace] . implode('/', $undefinedNamespaceFragments));
            }

            array_unshift($undefinedNamespaceFragments, array_pop($namespaceFragments));            
        }

        return false;
    }
}
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12 Comments

@PaulBasenko, Could you open an issue? I'd rather you report issues on Gitlab instead of here.
Oh, so do you still support this package?
Ok, thanks for reply. I didn't see that the package is freshly created, sorry))) If I'll reproduce the error in the future, I'll create an issue at the Gitlab package workflow.
It may be a universal approach but it is very slow. I tried to use your package in ZF3 with a big number of dependencies. The result - productivity suffers.
@dearsina, I'm not sure I fully understand what you mean by "executing" a class. I'm 90% sure the library does call class_exists() before returning them - I think that will cause an error if it tries to call that on a class that references non existent classes (for example, if you have classes that aren't deployed in production). That may or may not be what you're talking about. I'm definitely open to improvements if you have any suggestions, but I'd prefer for that discussion to occur on Gitlab rather than comments here :)
|
48

The generic approach would be to get all fully qualified classnames (class with full namespace) in your project, and then filter by the wanted namespace.

PHP offers some native functions to get those classes (get_declared_classes, etc), but they won't be able to find classes that have not been loaded (include / require), therefore it won't work as expected with autoloaders (like Composer for example). This is a major issue as the usage of autoloaders is very common.

So your last resort is to find all PHP files by yourself and parse them to extract their namespace and class:

$path = __DIR__;
$fqcns = array();

$allFiles = new RecursiveIteratorIterator(new RecursiveDirectoryIterator($path));
$phpFiles = new RegexIterator($allFiles, '/\.php$/');
foreach ($phpFiles as $phpFile) {
    $content = file_get_contents($phpFile->getRealPath());
    $tokens = token_get_all($content);
    $namespace = '';
    for ($index = 0; isset($tokens[$index]); $index++) {
        if (!isset($tokens[$index][0])) {
            continue;
        }
        if (
            T_NAMESPACE === $tokens[$index][0]
            && T_WHITESPACE === $tokens[$index + 1][0]
            && T_STRING === $tokens[$index + 2][0]
        ) {
            $namespace = $tokens[$index + 2][1];
            // Skip "namespace" keyword, whitespaces, and actual namespace
            $index += 2;
        }
        if (
            T_CLASS === $tokens[$index][0]
            && T_WHITESPACE === $tokens[$index + 1][0]
            && T_STRING === $tokens[$index + 2][0]
        ) {
            $fqcns[] = $namespace.'\\'.$tokens[$index + 2][1];
            // Skip "class" keyword, whitespaces, and actual classname
            $index += 2;

            # break if you have one class per file (psr-4 compliant)
            # otherwise you'll need to handle class constants (Foo::class)
            break;
        }
    }
}

If you follow PSR 0 or PSR 4 standards (your directory tree reflects your namespace), you don't have to filter anything: just give the path that corresponds to the namespace you want.

If you're not a fan of copying/pasting the above code snippets, you can simply install this library: https://github.com/gnugat/nomo-spaco . If you use PHP >= 5.5, you can also use the following library: https://github.com/hanneskod/classtools .

5 Comments

+1 for github.com/hanneskod/classtools - It's not immediately obvious how to use it to solve the problem in this exact question but with a little experimentation it does the job. It's quite a bit quicker than other packages/techniques listed here (probably because I can target a specific directory) but it's still relatively slow. I use it at build-time/deployment, so it's less of an issue. I would not run it in the browser request lifecycle.
What is the while loop for just after the namespace is captured? I've been testing and I could only see the need for the line $namespace .= $tokens[$index++][1]; so was hoping someone could enlighten me.
@Professorofprogramming good question. I can't remember the reasoning behind it, nor can find one as of now. I'll remove it
Since php 8.0, the token code for the namespace is not T_STRING anymore, but T_NAME_QUALIFIED instead.
@Professorofprogramming - the loop is/was necessary for PHP < 8.0 when Foo\Bar\Baz was 5 tokens vs 1 token
8

Quite a few interesting answers above, some actually peculiarly complex for the proposed task.

To add a different flavor to the possibilities, here a quick and easy non-optimized function to do what you ask using the most basic techniques and common statements I could think of:

function classes_in_namespace($namespace) {
      $namespace .= '\\';
      $myClasses  = array_filter(get_declared_classes(), function($item) use ($namespace) { return substr($item, 0, strlen($namespace)) === $namespace; });
      $theClasses = [];
      foreach ($myClasses AS $class):
            $theParts = explode('\\', $class);
            $theClasses[] = end($theParts);
      endforeach;
      return $theClasses;
}

Use simply as:

$MyClasses = classes_in_namespace('namespace\sub\deep');

var_dump($MyClasses);

I've written this function to assume you are not adding the last "trailing slash" (\) on the namespace, so you won't have to double it to escape it. ;)

Please notice this function is only an example and has many flaws. Based on the example above, if you use 'namespace\sub' and 'namespace\sub\deep' exists, the function will return all classes found in both namespaces (behaving as if it was recursive). However, it would be simple to adjust and expand this function for much more than that, mostly requiring a couple of tweaks in the foreach block.

It may not be the pinnacle of the code-art-nouveau, but at least it does what was proposed and should be simple enough to be self-explanatory.

I hope it helps pave the way for you to achieve what you are looking for.

Note: PHP 5, 7, AND 8 friendly.

9 Comments

As this is based on get_declared_class() it will only find classes that are already loaded. So IMO this solution is incomplete as it misses the main point of the question.
My apologies but I am not sure about what you mean... Please, enlight me: what is the main point of the question? In regards to your comment, of course get_declared_class() will only list classes that have been loaded. It applies to any inbuilt PHP function such as class_exists(), get_declared_interfaces(), and get_defined_functions() (just to name a few). If a file is not loaded, nothing from it yet exists. But, any junior programmer understands such obviousness and only invokes a function that accounts for "specifics" when they know the "specifics" they are accounting for are loaded.
Exactly, but the main point is: How to get all classes in a namespace even if they are not loaded. He already tried get_declared_classes() and it misses 2 unloaded classes. So that's not enough. And that's why the other answers are more complex as they include the part where they scan the directories to load all relevant class files.
Please read again this sentence in the question: *I tried get_declared_classes() inside getAllClasses() but MyClass1 and MyClass2 were not in the list.". So the questioner wants MyClass1 and MyClass2 even if they are not loaded. He already tried get_declared_classes() and it does not what he wants. So this answer adds nothing which is not already in the question.
@JulioMarchi If OP's classes weren't in the list returned by get_declared_classes() then by definition, the classes were not declared. Therefore, it doesn't answer the question. It may very well be @MichaelHärtl 's interpretation but then I'd have to say his interpreter is logically superior.
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6

Pretty interesting that there does not seem to be any reflection method that does that for you. However I came up with a little class that is capable of reading namespace information.

In order to do so, you have to traverse trough all defined classes. Then we get the namespace of that class and store it into an array along with the classname itself.

<?php

// ClassOne namespaces -> ClassOne
include 'ClassOne/ClassOne.php';

// ClassOne namespaces -> ClassTwo
include 'ClassTwo/ClassTwo.php';
include 'ClassTwo/ClassTwoNew.php';

// So now we have two namespaces defined 
// by ourselves (ClassOne -> contains 1 class, ClassTwo -> contains 2 classes)

class NameSpaceFinder {

    private $namespaceMap = [];
    private $defaultNamespace = 'global';

    public function __construct()
    {
        $this->traverseClasses();
    }

    private function getNameSpaceFromClass($class)
    {
        // Get the namespace of the given class via reflection.
        // The global namespace (for example PHP's predefined ones)
        // will be returned as a string defined as a property ($defaultNamespace)
        // own namespaces will be returned as the namespace itself

        $reflection = new \ReflectionClass($class);
        return $reflection->getNameSpaceName() === '' 
                ? $this->defaultNamespace
                : $reflection->getNameSpaceName();
    }

    public function traverseClasses()
    {
        // Get all declared classes
        $classes = get_declared_classes();

        foreach($classes AS $class)
        {
            // Store the namespace of each class in the namespace map
            $namespace = $this->getNameSpaceFromClass($class);
            $this->namespaceMap[$namespace][] = $class;
        }
    }

    public function getNameSpaces()
    {
        return array_keys($this->namespaceMap);
    }

    public function getClassesOfNameSpace($namespace)
    {
        if(!isset($this->namespaceMap[$namespace]))
            throw new \InvalidArgumentException('The Namespace '. $namespace . ' does not exist');

        return $this->namespaceMap[$namespace];
    }

}

$finder = new NameSpaceFinder();
var_dump($finder->getClassesOfNameSpace('ClassTwo'));

The output will be:

array(2) { [0]=> string(17) "ClassTwo\ClassTwo" [1]=> string(20) "ClassTwo\ClassTwoNew" }

Of course everything besides the NameSpaceFinder class itself if assembled quick and dirty. So feel free to clean up the include mess by using autoloading.

1 Comment

Actually auto-loading will break your solution as get_declared_classes() will only contain already auto-loaded classes. That would require MyClass1 and MyClass2 to be used (say 'auto-loaded') before you can find them.
6

After trying the composer solutions above, was not satisfied with the time it took to obtain the recursive classes inside a namespace, up to 3 seconds but on some machines it took 6-7 seconds which was unacceptable. Below class renders the classes in ~0.05 in a normal 3-4 levels depth directory structure.

namespace Helpers;

use RecursiveDirectoryIterator;
use RecursiveIteratorIterator;

class ClassHelper
{
    public static function findRecursive(string $namespace): array
    {
        $namespacePath = self::translateNamespacePath($namespace);

        if ($namespacePath === '') {
            return [];
        }

        return self::searchClasses($namespace, $namespacePath);
    }

    protected static function translateNamespacePath(string $namespace): string
    {
        $rootPath = __DIR__ . DIRECTORY_SEPARATOR;

        $nsParts = explode('\\', $namespace);
        array_shift($nsParts);

        if (empty($nsParts)) {
            return '';
        }

        return realpath($rootPath. implode(DIRECTORY_SEPARATOR, $nsParts)) ?: '';
    }

    private static function searchClasses(string $namespace, string $namespacePath): array
    {
        $classes = [];

        /**
         * @var \RecursiveDirectoryIterator $iterator
         * @var \SplFileInfo $item
         */
        foreach ($iterator = new RecursiveIteratorIterator(
            new RecursiveDirectoryIterator($namespacePath, RecursiveDirectoryIterator::SKIP_DOTS),
            RecursiveIteratorIterator::SELF_FIRST
        ) as $item) {
            if ($item->isDir()) {
                $nextPath = $iterator->current()->getPathname();
                $nextNamespace = $namespace . '\\' . $item->getFilename();
                $classes = array_merge($classes, self::searchClasses($nextNamespace, $nextPath));
                continue;
            }
            if ($item->isFile() && $item->getExtension() === 'php') {
                $class = $namespace . '\\' . $item->getBasename('.php');
                if (!class_exists($class)) {
                    continue;
                }
                $classes[] = $class;
            }
        }

        return $classes;
    }
}

Usage:

    $classes = ClassHelper::findRecursive(__NAMESPACE__);
    print_r($classes);

Result:

Array
(
    [0] => Helpers\Dir\Getters\Bar
    [1] => Helpers\Dir\Getters\Foo\Bar
    [2] => Helpers\DirSame\Getters\Foo\Cru
    [3] => Helpers\DirSame\Modifiers\Foo\Biz
    [4] => Helpers\DirSame\Modifiers\Too\Taz
    [5] => Helpers\DirOther\Modifiers\Boo
)

1 Comment

I tried haydenpierce/class-finder and it worked great but it was super slow. This was approach was fast.
6

Note: This solution seems to work with Laravel directly. For outside Laravel, you might need to copy and modify the ComposerClassMap class from the given source. I didn't try.

If you are already using Composer for PSR-4 compliant autoloading, you can use this method to get all autoloaded classes and filter them (That's the example from my module system, directly copied and pasted from there):

function get_available_widgets()
{
    $namespaces = array_keys((new ComposerClassMap)->listClasses());
    return array_filter($namespaces, function($item){
        return Str::startsWith($item, "App\\Modules\\Widgets\\") && Str::endsWith($item, "Controller");
    });
}

Source of the ComposerClassMap class: https://github.com/facade/ignition/blob/master/src/Support/ComposerClassMap.php

2 Comments

This answer looks great, but I can't find either ComposerClassMap or Str classes.
Str class belongs to Laravel, that's just there for giving an example. And you can find the source of ComposerClassMap here: github.com/facade/ignition/blob/master/src/Support/…
6

Using finder

composer require symfony/finder

usage

public function getAllNameSpaces($path)
{
    $filenames = $this->getFilenames($path);
    $namespaces = [];
    foreach ($filenames as $filename) {
        $namespaces[] = $this->getFullNamespace($filename) . '\\' . $this->getClassName($filename);
    }
    return $namespaces;
}

private function getClassName($filename)
{
    $directoriesAndFilename = explode('/', $filename);
    $filename = array_pop($directoriesAndFilename);
    $nameAndExtension = explode('.', $filename);
    $className = array_shift($nameAndExtension);
    return $className;
}

private function getFullNamespace($filename)
{
    $lines = file($filename);
    $array = preg_grep('/^namespace /', $lines);
    $namespaceLine = array_shift($array);
    $match = [];
    preg_match('/^namespace (.*);$/', $namespaceLine, $match);
    $fullNamespace = array_pop($match);

    return $fullNamespace;
}

private function getFilenames($path)
{
    $finderFiles = Finder::create()->files()->in($path)->name('*.php');
    $filenames = [];
    foreach ($finderFiles as $finderFile) {
        $filenames[] = $finderFile->getRealpath();
    }
    return $filenames;
}

Comments

5

I think a lot of people might have a problem like this, so I relied on the answers from @hpierce and @loïc-faugeron to solve this problem.

With the class described below, you can have all classes within a namespace or they respect a certain term.

<?php

namespace Backup\Util;

final class ClassFinder
{
    private static $composer = null;
    private static $classes  = [];

    public function __construct()
    {
        self::$composer = null;
        self::$classes  = [];

        self::$composer = require APP_PATH . '/vendor/autoload.php';

        if (false === empty(self::$composer)) {
            self::$classes  = array_keys(self::$composer->getClassMap());
        }
    }

    public function getClasses()
    {
        $allClasses = [];

        if (false === empty(self::$classes)) {
            foreach (self::$classes as $class) {
                $allClasses[] = '\\' . $class;
            }
        }

        return $allClasses;
    }

    public function getClassesByNamespace($namespace)
    {
        if (0 !== strpos($namespace, '\\')) {
            $namespace = '\\' . $namespace;
        }

        $termUpper = strtoupper($namespace);
        return array_filter($this->getClasses(), function($class) use ($termUpper) {
            $className = strtoupper($class);
            if (
                0 === strpos($className, $termUpper) and
                false === strpos($className, strtoupper('Abstract')) and
                false === strpos($className, strtoupper('Interface'))
            ){
                return $class;
            }
            return false;
        });
    }

    public function getClassesWithTerm($term)
    {
        $termUpper = strtoupper($term);
        return array_filter($this->getClasses(), function($class) use ($termUpper) {
            $className = strtoupper($class);
            if (
                false !== strpos($className, $termUpper) and
                false === strpos($className, strtoupper('Abstract')) and
                false === strpos($className, strtoupper('Interface'))
            ){
                return $class;
            }
            return false;
        });
    }
}

In this case, you must use Composer to perform class autoloading. Using the ClassMap available on it, the solution is simplified.

2 Comments

Note, that you have to generate an optimized autoloader, using the -o option for this to work with all classes. composer dump-autoload -o
Yeap! Auto-generate and you all good. Pretty fast! Prefer this over the rest
3

I am going to give an example which is actually being used in our Laravel 5 app but can be used almost everywhere. The example returns class names with the namespace which can be easily taken out, if not required.

Legend

  • {{1}} - Path to remove from current file's path to get to app folder
  • {{2}} - The folder path from app folder where the target classes exist
  • {{3}} - Namespace path

Code

$classPaths = glob(str_replace('{{1}}', '',__DIR__) .'{{2}}/*.php');
$classes = array();
$namespace = '{{3}}';
foreach ($classPaths as $classPath) {
    $segments = explode('/', $classPath);
    $segments = explode('\\', $segments[count($segments) - 1]);
    $classes[] = $namespace . $segments[count($segments) - 1];
}

Laravel people can use app_path() . '/{{2}}/*.php' in glob().

Comments

2

Locate Classes

A class can be found in the file system by its name and its namespace, like the autoloader does. In the normal case the namespace should tell the relative path to the class files. The include paths are the starting points of the relative paths. The function get_include_path() returns a list of include paths in one string. Each include path can be tested, whether there exists a relative path which matches the namespace. If the matching path is found, you will know the location of the class files.

Get Class Names

As soon as the location of the class files is known, the classes can be extracted from the file names, because the name of a class file should consist of the class name followed by .php.

Sample Code

Here is a sample code to get all class names of the namespace foo\bar as a string array:

$namespace = 'foo\bar';

// Relative namespace path
$namespaceRelativePath = str_replace('\\', DIRECTORY_SEPARATOR, $namespace);

// Include paths
$includePathStr = get_include_path();
$includePathArr = explode(PATH_SEPARATOR, $includePathStr);

// Iterate include paths
$classArr = array();
foreach ($includePathArr as $includePath) {
    $path = $includePath . DIRECTORY_SEPARATOR . $namespaceRelativePath;
    if (is_dir($path)) { // Does path exist?
        $dir = dir($path); // Dir handle     
        while (false !== ($item = $dir->read())) {  // Read next item in dir
            $matches = array();
            if (preg_match('/^(?<class>[^.].+)\.php$/', $item, $matches)) {
                $classArr[] = $matches['class'];
            }
        }
        $dir->close();
    }
}

// Debug output
var_dump($includePathArr);
var_dump($classArr);

Comments

1

class_parents, spl_classes() and class_uses can be used to retrieve all the class names

Comments

0

The easiest way should be to use your own autoloader __autoload function and inside of it save the loaded classes names. Does that suits You ?

Otherwise I think You will have to deal with some reflection methods.

1 Comment

I think you have to know the class names in order to use __autoload. example: $a = new MyClass1(). I only know the namespace, not the class names.
0

You can use get_declared_classes but with a little additional work.

$needleNamespace = 'MyNamespace';
$classes = get_declared_classes();
$neededClasses = array_filter($classes, function($i) use ($needleNamespace) {
    return strpos($i, $needleNamespace) === 0;
});

So first you get all declared classes and then check which of them starts with your namespace.

Note: you will get array where keys do not start with 0. To achive this, you can try: array_values($neededClasses);.

1 Comment

Nice and short and gives you ultimate flexibility. However be aware that one should include \\ after the namespace to exclude any namespace that contains the namespace of the needle. Like in the namespace App, the class AppendIterator would be included aswell.
0

I just did something similar, this is relatively simple but can be built off of.

  public function find(array $excludes, ?string $needle = null)
  {
    $path = "../".__DIR__;
    $files = scandir($path);
    $c = count($files);
    $models = [];
    for($i=0; $i<$c; $i++) {
      if ($files[$i] == "." || $files[$i] == ".." || in_array($dir[$i], $excludes)) {
        continue;
      }
      $model = str_replace(".php","",$dir[$i]);
      if (ucfirst($string) == $model) {
        return $model;
      }
      $models[] = $model;
    }
    return $models;
  }

Comments

-1

for symfony you can use the Finder Component:

http://symfony.com/doc/current/components/finder.html

$result1 = $finder->in(__DIR__)->files()->contains('namespace foo;');
$result2 = $finder->in(__DIR__)->files()->contains('namespace bar;');

Comments

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