For Loop Table in PHP

Question

I am trying to generate a table with php for loop, that lists numbers. Something like this:

1 | 2 | 3 | 4 | 5
2 | 3 | 4 | 5 | 1
3 | 4 | 5 | 1 | 2
4 | 5 | 1 | 2 | 3
5 | 1 | 2 | 3 | 4

I still have problems getting it, this is actually quite simple, but I have not been able to solve it. So far I have the following code:

<?php
echo "<table border='1'><br />";

for ($row = 0; $row < 5; $row ++) {
   echo "<tr>";

   for ($col = 1; $col <= 4; $col ++) {
        echo "<td>", ($col + ($row * 4)), "</td>";
   }

   echo "</tr>";
}

echo "</table>";
?>

However, this only generates the following:

1  | 2  | 3  | 4 
5  | 6  | 7  | 8
9  | 10 | 11 | 12
13 | 14 | 15 | 16
17 | 18 | 19 | 20

Thank you, any help would be appreciated!

This should give you an idea $a = array(1,2,3,4,5); array_unshift($a, array_pop($a)); — Rodrigo Siqueira
– Rodrigo Siqueira, Commented Apr 1, 2014 at 13:37
This is called "queue" in data structures. Read this phpmoot.com/other-sorting-options — Ahmad Essam
– Ahmad Essam, Commented Apr 1, 2014 at 13:47

remudada · Accepted Answer · 2014-04-01 13:33:13Z

18

<?php
echo "<table border='1'><br />";

for ($row = 0; $row < 5; $row ++) {
   echo "<tr>";

   for ($col = 0; $col < 5; $col ++) {
        echo "<td>", (($col + $row) % 5) + 1, "</td>";
   }

   echo "</tr>";
}

echo "</table>";
?>

answered Apr 1, 2014 at 13:33

remudada

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Comments

blue · Accepted Answer · 2014-04-01 13:35:20Z

6

echo "<table border='1'><br />";
for ( $i = 0; $i < 5; $i++ ) {
    echo "<tr>";
    for ( $j = 0; $j < 5; $j++ ) {
        echo "<td>", ($j+$i)%5+1, "</td>";
    }
    echo "</tr>";
}
echo "</table>";

answered Apr 1, 2014 at 13:35

blue

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Comments

Hackerman · Accepted Answer · 2014-04-01 13:42:43Z

3

My version :

<?php
echo "<table border='1'><br />";
$i=1;
for ($row = 0; $row < 5; $row ++) {
  echo "<tr>";
  $cont = 0;
for ($col = $i; $col <= 5; $col ++) 
    {
     echo "<td>", ($col), "</td>";
     $cont++;
    }
if($cont < 5)
{
 for($col = 1; $col <= 5 - $cont; $col++)
 {
  echo "<td>", ($col), "</td>";
 }
 }

echo "</tr>";
$i++;
}

echo "</table>";

Codepad: http://codepad.viper-7.com/JZogNY

answered Apr 1, 2014 at 13:42

Hackerman

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Comments

Ali Nouman · Accepted Answer · 2014-04-01 16:37:11Z

2

My Version

<?php
echo "<table border='1'><br />";

for ($row = 0; $row < 5; $row ++) {
   $k=$row;

   for ($col = 0; $col < 5; $col ++) {
        echo "<td>", (($k++)%5)+1, "</td>";
   }

   echo "</tr>";
}

echo "</table>";
?>

answered Apr 1, 2014 at 16:37

Ali Nouman

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Comments

Ruiz24 · Accepted Answer · 2018-01-25 19:11:56Z

0

<?php

    echo '<table border="1">';
    $i = 0;
    for($i =1; $i<=5; $i++){
        echo '<tr>
            <td>'.$i.'</td>';
            $x = 0;
            for($x=1; $x<=4; $x++){
                $y = $x + $i;
                $z = ($y>5) ? $y-5 : $y;
                echo '<td>'.$z.'</td>';
            }
        echo '</tr>';
    }

    echo '</table>';
?>

answered Jan 25, 2018 at 19:11

Ruiz24

1

1 Comment

Prakash Palnati Over a year ago

consider adding the explanation rather than adding the code.

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